正则表达式\p {Punct}错过了java中的unicode标点符号

本文介绍了正则表达式\p {Punct}错过了java中的unicode标点符号的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我写了一个小测试来证明

I wrote a little test to demonstrate

@Test public void missingPunctuationRegex() { Pattern punct = Patternpile("[\\p{Punct}]"); Matcher m = punct.matcher("'"); assertTrue("ascii puctuation", m.find()); m = punct.matcher("‘"); assertTrue("unicode puctuation", m.find()); }

第一个断言通过，第二个失败。您可能不得不眯着眼睛看它，但那是左单引号（ U + 2018 ）并且应该作为标点符号覆盖。据我所知。

The first assert passes, and the second one fails. You may have to squint to see it, but that is the 'LEFT SINGLE QUOTATION MARK' (U+2018) and should be covered as a punctuation as far as I can tell.

我如何匹配Java正则表达式中的所有标点符号？

How would I match ALL punctuations in Java regular expressions?

推荐答案

你可以使用 UNICODE_CHARACTER_CLASS 标记为 \ p {Punct} 匹配所有Unicode标点符号。

You can use the UNICODE_CHARACTER_CLASS flag to make \p{Punct} match all Unicode punctuation.