在java中将两个整数分成两个

本文介绍了在java中将两个整数分成两个的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我可以看到这是新程序员的常见问题，但是我没有成功地实现我的代码的任何解决方案。基本上我想划分w和v，它必须保存到一个double变量中。但是它打印[0.0，0.0，...，0.0]

I can see this is a common problem for new programmers, however I didn't succeed in implementing any of the solution to my code. Basically I want to divide w and v, which must be saved to a double variable. But it prints [0.0, 0.0, ... , 0.0]

public static double density(int[] w, int[] v){ double d = 0; for(L = 0; L < w.length; L++){ d = w[L] /v[L]; } return d; }

推荐答案

这行这里 d = w [L] / v [L]; 发生在几个步骤

This line here d = w[L] /v[L]; takes place over several steps

d = (int)w[L] / (int)v[L] d=(int)(w[L]/v[L]) //the integer result is calculated d=(double)(int)(w[L]/v[L]) //the integer result is cast to double

$ b $换句话说，精确度已经在你转换成双倍之前就已经消失了，所以你需要先转一次，所以

In other words the precision is already gone before you cast to double, you need to cast to double first, so

d = ((double)w[L]) / (int)v[L];

这将强制java使用双重数学，而不是使用整数数学，然后转换为双精度在结尾

This forces java to use double maths the whole way through rather than use integer maths and then cast to double at the end