Cocoa：在屏幕上获取当前鼠标位置

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我需要在Mac上使用Xcode在屏幕上获取鼠标位置。我有一些代码，据说这样做，但我总是返回x和y为0：

I need to get the mouse position on the screen on a Mac using Xcode. I have some code that supposedly does that but i always returns x and y as 0:

void queryPointer() { NSPoint mouseLoc; mouseLoc = [NSEvent mouseLocation]; //get current mouse position NSLog(@"Mouse location:"); NSLog(@"x = %d", mouseLoc.x); NSLog(@"y = %d", mouseLoc.y); }

我做错了什么？如何获得屏幕上的当前位置？ 此外，最终该位置（保存在NSPoint中）需要复制到CGPoint中以与另一个函数一起使用，因此我需要将它作为x，y坐标或翻译这个。

What am I doing wrong? How do you get the current position on the screen? Also, ultimately that position (saved in a NSPoint) needs to be copied into a CGPoint to be used with another function so i need to get this either as x,y coordinates or translate this.

推荐答案

CGEventRef ourEvent = CGEventCreate(NULL); point = CGEventGetLocation(ourEvent); CFRelease(ourEvent); NSLog(@"Location? x= %f, y = %f", (float)point.x, (float)point.y);