我的C ++代码出现错误,我无法理解。剥离的代码位在这里:
I'm getting an error in my C++ code that I can't quite make sense of. The stripped down code bits are here:
RS232Handle=OpenRS232("COM1", 9600); HANDLE OpenRS232(const char* ComName, DWORD BaudRate) { ComHandle=CreateFile(ComName, GENERIC_READ|GENERIC_WRITE, 0, NULL, OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL, NULL); }我收到以下错误:
error: cannot convert 'const char*' to 'LPCWSTR {aka const wchar_t*}' for argument '1' to 'void* CreateFileW(LPCWSTR, DWORD, DWORD, LPSECURITY_ATTRIBUTES, DWORD, DWORD, HANDLE)' ComHandle=CreateFile(ComName, GENERIC_READ|GENERIC_WRITE, 0, NULL, OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL, NULL);该代码取自VS代码,我现在使用的是Qt Creator。
The code was taken from VS code and I am now using Qt creator.
如何解决此问题?谢谢!
How can I fix this issue? Thanks!
推荐答案Windows CreateFile 函数实际上是一个扩展为以下其中之一的宏:
The Windows CreateFile function is actually a macro that expands to one of:
- CreateFileA ,其文件类型为 const char *
- CreateFileW ,该文件路径的类型为 const wchar_t * 。
- CreateFileA, which takes a file path of type const char*
- CreateFileW, which takes a file path of type const wchar_t*.
(对于Windows API中大多数采用字符串的功能,都是如此。)
(The same is true for most of the functions in the Windows API that take a string.)
您要声明参数 const char * ComName ,但显然使用已定义的 UNICODE 进行编译,因此它正在调用该函数的 W 版本。从 const wchar_t * 到 const char * 不会自动转换,因此会出错。
You're declaring the parameter const char* ComName, but apparently compiling with UNICODE defined, so it's calling the W version of the function. There's no automatic conversion from const wchar_t* to const char*, hence the error.
您的选项是:
编辑:,我不知道涉及绑架,但Windows 10 1903最终添加了支持将UTF-8作为ANSI代码页。
I don't know if a kidnapping was involved, but Windows 10 1903 finally added support for UTF-8 as an ANSI code page.
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无法将'const char *'转换为'LPCWSTR {aka const wchar
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