Gmail PHP API发送电子邮件

本文介绍了Gmail PHP API发送电子邮件的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述

我正在尝试通过Gmail PHP API发送电子邮件( developers.google/gmail/api/v1/reference/users/messages/send ).一切似乎都可以完成，直到我发送邮件为止.我的代码是:

I am trying to send an email through the Gmail PHP API (developers.google/gmail/api/v1/reference/users/messages/send). Everything seems to work up to the point that I send the message. My code is:

private function createMessage($email) { $message = new Google_Service_Gmail_Message(); $message->setRaw(strtr(base64_encode($email), '+/=', '-_,')); // $email is a raw email data string return $message; } public function sendMessage($userID, $email) { try { $msg = $this->createMessage($email); $this->service->users_messages->send($userID, $msg); } catch (Exception $e) { print 'An error occurred: ' . $e->getMessage(); } }

代码在以下行中断:

$this->service->users_messages->send($userID, $msg);

出现错误:

An error occurred: Error calling POST www.googleapis/gmail/v1/users/myemailaddress@gmail/messages/send: (400) Invalid value for ByteString:

你知道这里发生了什么吗?谢谢！

Any idea what is happening here? Thanks!

推荐答案

您设置为原始"的电子邮件字符串必须使用 URL安全 base64编码(字母略有不同).

The email string you set to 'raw' needs to be url safe base64 encoded (slightly different alphabet).