我用引导我的C＃asp项目，我想显示显示从后面的代码模式弹出。
i am using bootstrap in my c# asp project and i want to show to show the modal popup from code behind.
在我的网页标题，我有一个javascript函数如下：
in my page header i have a javascript function as follows:
function LoginFail() { $('#windowTitleDialog').modal('show'); }和我按一下按钮我打电话的JavaScript如下：
and on the click of my button i am calling the javascript as follows
ScriptManager.RegisterClientScriptBlock(this, typeof(System.Web.UI.Page), "LoginFail", "LoginFail();", true);这不显示模式弹出。不过，如果我使用像警报（'登录失败'），它工作正常。
this does not show the modal popup. however, if i use something like alert('login failed'), it works fine.
任何人可以请与帮助呢？
can anybody please help with this?
推荐答案在默认情况下引导的JavaScript文件只是在结束标记之前包括
By default Bootstrap javascript files are included just before the closing body tag
<script src="vendors/jquery-1.9.1.min.js"></script> <script src="bootstrap/js/bootstrap.min.js"></script> <script src="vendors/easypiechart/jquery.easy-pie-chart.js"></script> <script src="assets/scripts.js"></script> </body>
我把这些JavaScript文件到头部分身体标记之前，我写了一个小功能调用模式弹出：
I took these javascript files into the head section right before the body tag and I wrote a small function to call the modal popup:
<script src="vendors/jquery-1.9.1.min.js"></script> <script src="bootstrap/js/bootstrap.min.js"></script> <script src="vendors/easypiechart/jquery.easy-pie-chart.js"></script> <script src="assets/scripts.js"></script> <script type="text/javascript"> function openModal() { $('#myModal').modal('show'); } </script> </head> <body>
然后我可以调用从代码隐藏模式弹出与以下内容：
then I could call the modal popup from code-behind with the following:
protected void lbEdit_Click(object sender, EventArgs e) { ScriptManager.RegisterStartupScript(this,this.GetType(),"Pop", "openModal();", true); }更多推荐
引导模式弹出C＃代码隐藏
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