我正在尝试将图片上传到restApi，但它会引发内部服务器错误。 请考虑我的代码并指导我在哪里找不到的东西
public void UploadAsset（ string sToken， string sImage） { string sRes = string .Empty; Uri地址= new Uri（ services-sandbox.sheerid/rest/0.5/asset）; // 创建网络请求 HttpWebRequest oHttpWebRequest = WebRequest .Create（address） as HttpWebRequest; oHttpWebRequest.Credentials = new NetworkCredential（ mrinalkumarjha， ******）; oHttpWebRequest.Headers [ 授权] = Bearer 624a3eef46f79772958693fa87118b29; oHttpWebRequest.Method = POST; oHttpWebRequest.ContentType = multipart / form-data; // 创建我们要发送的数据 string sFile = asset.png; StringBuilder data = new StringBuilder（）; data.Append（ file = + HttpUtility.UrlEncode（@sFile））; data.Append（ & failure = + HttpUtility.UrlEncode（ 您的网址））; data.Append（ & succes = + HttpUtility.UrlEncode（ 您的网址））; data.Append（ & token = + HttpUtility.UrlEncode（txtToken.Text ））; // 创建我们要发送的数据的字节数组 byte [] byteData = UTF8Encoding.UTF8.GetBytes（data.ToString（））; // 在请求标题中设置内容长度 oHttpWebRequest.ContentLength = byteData.Length; // 写入数据。 使用（Stream postStream = oHttpWebRequest.GetRequestStream（）） { postStream.Write（byteData， 0 ，byteData.Length）; } // 获取回复 使用（HttpWebResponse响应= oHttpWebRequest.GetResponse（）作为 HttpWebResponse） { // 获取响应流 StreamReader reader = new StreamReader（response.GetResponseStream（））; // 控制台应用程序输出 sRes = reader.ReadToEnd （）; } }已添加代码块[/ Edit]
解决方案我已经解决了..在类文件中添加以下内容。 private static readonly编码encoding = Encoding.UTF8; 公共静态HttpWebResponse MultipartFormDataPost（串postUrl，串的userAgent，字典<字符串> postParameters） { 串formDataBoundary =的String.Format（ - --------- {0：N}，Guid.NewGuid（））; string contentType =multipart / form-data; boundary =+ formDataBoundary; byte [] formData = GetMultipartFormData（postParameters，formDataBoundary）; 返回PostForm（postUrl，userAgent，contentType， formData）; } private static HttpWebResponse PostForm（string postUrl，string userAgent，string contentType，byte [] formData） { HttpWebRequest request = WebRequest.Create（postUrl）as HttpWebRequ est; if（request == null） { 抛出新的NullReferenceException（请求不是一个http请求）; } //设置请求属性。 request.Method =POST; request.ContentType = contentType; request.UserAgent = userAgent; request.CookieContainer = new CookieContainer（）; request.ContentLength = formData.Length; request.Credentials = new NetworkCredential（mrinalkumarjha，***** ）; request.Headers [Authorization] =Bearer 624a3eef46f79772958693fa87118b29; //你也可以在这里添加身份验证需要： // request.PreAuthenticate = true; // request.AuthenticationLevel = System.Net.Security.AuthenticationLevel.MutualAuthRequested; // request.Headers.Add（Authorization，Basic+ Convert.ToBase64String（System.Text.Encoding.D efault.GetBytes（用户名+：+密码）））; //将表单数据发送到请求。 using（Stream requestStream = request.GetRequestStream（）） { requestStream.Write（formData，0，formData.Length）; requestStream.Close（）; } 返回request.GetResponse（）as HttpWebResponse; } $ / $ private static byte [] GetMultipartFormData（Dictionary< string，> postParameters，string boundary） { Stream formDataStream = new System.IO.MemoryStream（）; bool needsCLRF = false; foreach（postParameters中的var param） { //感谢评论者的反馈，添加CRLF以允许要添加多个参数。 //在第一个参数上跳过它，将其添加到后续参数中。 if（needsCLRF） formDataStream .Write（encoding.GetBytes（\\\\ n），0，encoding.GetByteCount（\\\\ n））; needsCLRF = true; if（param.Value is FileParameter） { FileParameter fileToUpload =（FileParameter ）param.Value; //只添加此参数的第一部分，因为我们将文件数据直接写入Stream string header = string.Format（ - {0} \\\\ nConContent-Disposition：form-data; name = \{1} \ ; filename = \{2} \; \\\Content-Type：{3} \\\\\\\ n， border， param.Key， fileToUpload.FileName ?? param.Key， fileToUpload.ContentType ?? application / octet-stream）; formDataStream.Write（encoding.GetBytes（header），0，encoding.GetByteCount（header））; //将文件数据直接写入Stream，而不是将其序列化为字符串。 formDataStream.Write（fileToUpload.File，0，fileToUpload .File.Length）; } else { string postData = string.Format（ - - {0} \\\\ nnContent-Disposition：form-data; name = \{1} \\\\\\ n {2}， 边界， param.Key， param.Value）; formDataStream.Write（encoding.GetBytes（postData），0 ，encoding.GetByteCount（postData））; } } //添加结束请求。从换行符开始 string footer =\\\\ n - + boundary +--\\\\ n; formDataStream.Write （encoding.GetBytes（footer），0，encoding.GetByteCount（footer））; //将Stream转储成一个字节[] formDataStream.Position = 0; byte [] formData = new byte [formDataStream.Length]; formDataStream.Read（formData，0，formData.Length）; formDataStream.Close（）; 返回formData; } 公共类FileParameter { public byte [] File {get;组; } $ / $ 公共字符串FileName {get;组; } $ / $ 公共字符串ContentType {get;组; } $ / $ public FileParameter（byte [] file）：this（file，null）{} public FileParameter（byte [] file，string filename）：this（file， filename，null）{} public FileParameter（byte [] file，string filename，string contenttype） { File = file; FileName = filename; ContentType = contenttype; } } 现在从aspx.cs页面调用..就像这样.. !! protected void btnUploadAsset_Click（object sender，EventArgs e） { //读取文件数据 string strPath = Server.MapPath（〜/ shopping / asset.png）; FileStream fs = new FileStream（strPath，FileMode.Open，FileAccess.Read）; byte [] data = new byte [fs.Length]; fs.Read（data，0，data.Length）; fs.Close（）; //生成帖子对象 Dictionary< string，> postParameters = new Dictionary< string，>（）; postParameters.Add（token，txtToken.Text）; // @ postParameters.Add（fileformat ，png）; postParameters.Add（file，new SheerIdcl.FileParameter（data，asset.png，image / png））; //创建请求并收到回复 string postURL =services-sandbox.sheerid/rest/0.5/asset\"; 串的userAgent = Mozila; HttpWebResponse WebResponse类= SheerIdcl.MultipartFormDataPost（postURL，的userAgent，postParameters）; //处理响应 的StreamReader responseReader =新的StreamReader（webResponse.GetResponseStream（））; 串fullResponse = responseReader.ReadToEnd（）; webResponse.Close（）; ltrUploadResponse.Text = fullResponse; }
I am trying to upload image to restApi but it throws Internal server error. Please consider my code and guide me where i am missing something
public void UploadAsset(string sToken, string sImage) { string sRes = string.Empty; Uri address = new Uri("services-sandbox.sheerid/rest/0.5/asset"); // Create the web request HttpWebRequest oHttpWebRequest = WebRequest.Create(address) as HttpWebRequest; oHttpWebRequest.Credentials = new NetworkCredential("mrinalkumarjha", "******"); oHttpWebRequest.Headers["Authorization"] = "Bearer 624a3eef46f79772958693fa87118b29"; oHttpWebRequest.Method = "POST"; oHttpWebRequest.ContentType = "multipart/form-data"; // Create the data we want to send string sFile = "asset.png"; StringBuilder data = new StringBuilder(); data.Append("file=" + HttpUtility.UrlEncode(@sFile)); data.Append("&failure=" + HttpUtility.UrlEncode("Your URL")); data.Append("&succes=" + HttpUtility.UrlEncode("Your URL")); data.Append("&token=" + HttpUtility.UrlEncode(txtToken.Text)); // Create a byte array of the data we want to send byte[] byteData = UTF8Encoding.UTF8.GetBytes(data.ToString()); // Set the content length in the request headers oHttpWebRequest.ContentLength = byteData.Length; // Write data. using (Stream postStream = oHttpWebRequest.GetRequestStream()) { postStream.Write(byteData, 0, byteData.Length); } // Get response using (HttpWebResponse response = oHttpWebRequest.GetResponse() as HttpWebResponse) { // Get the response stream StreamReader reader = new StreamReader(response.GetResponseStream()); // Console application output sRes = reader.ReadToEnd(); } }[Edit]Code block added[/Edit]
解决方案 I have solved it .. add following in class file. private static readonly Encoding encoding = Encoding.UTF8; public static HttpWebResponse MultipartFormDataPost(string postUrl, string userAgent, Dictionary<string,> postParameters) { string formDataBoundary = String.Format("----------{0:N}", Guid.NewGuid()); string contentType = "multipart/form-data; boundary=" + formDataBoundary; byte[] formData = GetMultipartFormData(postParameters, formDataBoundary); return PostForm(postUrl, userAgent, contentType, formData); } private static HttpWebResponse PostForm(string postUrl, string userAgent, string contentType, byte[] formData) { HttpWebRequest request = WebRequest.Create(postUrl) as HttpWebRequest; if (request == null) { throw new NullReferenceException("request is not a http request"); } // Set up the request properties. request.Method = "POST"; request.ContentType = contentType; request.UserAgent = userAgent; request.CookieContainer = new CookieContainer(); request.ContentLength = formData.Length; request.Credentials = new NetworkCredential("mrinalkumarjha", "*****"); request.Headers["Authorization"] = "Bearer 624a3eef46f79772958693fa87118b29"; // You could add authentication here as well if needed: // request.PreAuthenticate = true; // request.AuthenticationLevel = System.Net.Security.AuthenticationLevel.MutualAuthRequested; // request.Headers.Add("Authorization", "Basic " + Convert.ToBase64String(System.Text.Encoding.Default.GetBytes("username" + ":" + "password"))); // Send the form data to the request. using (Stream requestStream = request.GetRequestStream()) { requestStream.Write(formData, 0, formData.Length); requestStream.Close(); } return request.GetResponse() as HttpWebResponse; } private static byte[] GetMultipartFormData(Dictionary<string,> postParameters, string boundary) { Stream formDataStream = new System.IO.MemoryStream(); bool needsCLRF = false; foreach (var param in postParameters) { // Thanks to feedback from commenters, add a CRLF to allow multiple parameters to be added. // Skip it on the first parameter, add it to subsequent parameters. if (needsCLRF) formDataStream.Write(encoding.GetBytes("\r\n"), 0, encoding.GetByteCount("\r\n")); needsCLRF = true; if (param.Value is FileParameter) { FileParameter fileToUpload = (FileParameter)param.Value; // Add just the first part of this param, since we will write the file data directly to the Stream string header = string.Format("--{0}\r\nContent-Disposition: form-data; name=\"{1}\"; filename=\"{2}\";\r\nContent-Type: {3}\r\n\r\n", boundary, param.Key, fileToUpload.FileName ?? param.Key, fileToUpload.ContentType ?? "application/octet-stream"); formDataStream.Write(encoding.GetBytes(header), 0, encoding.GetByteCount(header)); // Write the file data directly to the Stream, rather than serializing it to a string. formDataStream.Write(fileToUpload.File, 0, fileToUpload.File.Length); } else { string postData = string.Format("--{0}\r\nContent-Disposition: form-data; name=\"{1}\"\r\n\r\n{2}", boundary, param.Key, param.Value); formDataStream.Write(encoding.GetBytes(postData), 0, encoding.GetByteCount(postData)); } } // Add the end of the request. Start with a newline string footer = "\r\n--" + boundary + "--\r\n"; formDataStream.Write(encoding.GetBytes(footer), 0, encoding.GetByteCount(footer)); // Dump the Stream into a byte[] formDataStream.Position = 0; byte[] formData = new byte[formDataStream.Length]; formDataStream.Read(formData, 0, formData.Length); formDataStream.Close(); return formData; } public class FileParameter { public byte[] File { get; set; } public string FileName { get; set; } public string ContentType { get; set; } public FileParameter(byte[] file) : this(file, null) { } public FileParameter(byte[] file, string filename) : this(file, filename, null) { } public FileParameter(byte[] file, string filename, string contenttype) { File = file; FileName = filename; ContentType = contenttype; } } Now call it from aspx.cs page.. Like this..!! protected void btnUploadAsset_Click(object sender, EventArgs e) { // Read file data string strPath = Server.MapPath("~/shopping/asset.png"); FileStream fs = new FileStream(strPath, FileMode.Open, FileAccess.Read); byte[] data = new byte[fs.Length]; fs.Read(data, 0, data.Length); fs.Close(); // Generate post objects Dictionary<string,> postParameters = new Dictionary<string,>(); postParameters.Add("token", txtToken.Text); //postParameters.Add("fileformat", "png"); postParameters.Add("file", new SheerIdcl.FileParameter(data, "asset.png", "image/png")); // Create request and receive response string postURL = "services-sandbox.sheerid/rest/0.5/asset"; string userAgent = "Mozila"; HttpWebResponse webResponse = SheerIdcl.MultipartFormDataPost(postURL, userAgent, postParameters); // Process response StreamReader responseReader = new StreamReader(webResponse.GetResponseStream()); string fullResponse = responseReader.ReadToEnd(); webResponse.Close(); ltrUploadResponse.Text = fullResponse; }更多推荐
将图像上传到REST API的问题.. !!
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