在Mysql和php中使用foreach显示两个数组的值并将其保存在数据库中(Display the values of two arrays and save it in the database

我有两个数组，包含子名称的数组，另一个数组包含孩子的生日。 这是我的表单的设计，用户将填满。

<div id="Children">
  <div class="form-group col-md-7">
    <label for="child">Name of Child</label>
    <input type="text" class="form-control" name="child[]" id="child" placeholder="FULL NAME">
  </div>

  <div class="form-group col-md-5">
    <label for="ch_DateOfBirth">Date of Birth</label>
    <input type="text" class="form-control date-picker" name="ch_DateOfBirth[]" id="DateOfBirth" placeholder="Date of Birth">

  </div> 
  
 
 
 这是我的PHP代码，用于将两个数组保存在数据库中。 
 
 
 
  
  
$child_name=$_POST['child'];
$child_bday=date('Y-d-m', strtotime($_POST['ch_DateOfBirth']));
$count=count($child_name);

for ($i=0; $i < $count ; $i++) { 
  $sql6="INSERT into  tbl_children (Emp_ID, Ch_Name, Ch_Bdate) values ('".$emp_id."', '".$child_name[$i]."', '".$child_bday[$i]."') ";
    $dbcon->query($sql6);
} 
  
 
 
 但每当我试图这样做，只有孩子的名字被保存，不包括他们的生日。 如果可能，我如何使用foreach保存它？ 
 
  
I have two arrays, the array that holds the child name and the other one is an array that holds the birthday of the child. This is the design of my form that the user will fill up. 
 
 
 
  
  
<div id="Children">
  <div class="form-group col-md-7">
    <label for="child">Name of Child</label>
    <input type="text" class="form-control" name="child[]" id="child" placeholder="FULL NAME">
  </div>

  <div class="form-group col-md-5">
    <label for="ch_DateOfBirth">Date of Birth</label>
    <input type="text" class="form-control date-picker" name="ch_DateOfBirth[]" id="DateOfBirth" placeholder="Date of Birth">

  </div> 
  
 
 
and this is my php code for saving the two arrays in the database.
 
 
 
  
  
$child_name=$_POST['child'];
$child_bday=date('Y-d-m', strtotime($_POST['ch_DateOfBirth']));
$count=count($child_name);

for ($i=0; $i < $count ; $i++) { 
  $sql6="INSERT into  tbl_children (Emp_ID, Ch_Name, Ch_Bdate) values ('".$emp_id."', '".$child_name[$i]."', '".$child_bday[$i]."') ";
    $dbcon->query($sql6);
} 
  
 
 
but whenever i tried to do so, only the name of the children are saved excluding their birthdays. How can I save it using foreach if possible? 
 

                
最满意答案
                
                    
                        
 希望这会起作用 
 
$child_name=$_POST['child'];
$count=count($child_name);

for ($i=0; $i < $count ; $i++) {
  $child_bday=date('Y-d-m', strtotime($_POST['ch_DateOfBirth'][$i]));
  $sql6="INSERT into  tbl_children (Emp_ID, Ch_Name, Ch_Bdate) values ('".$emp_id."', '".$child_name[$i]."', '".$child_bday."') ";
  $dbcon->query($sql6);
}
Hope this will works
 
$child_name=$_POST['child'];
$count=count($child_name);

for ($i=0; $i < $count ; $i++) {
  $child_bday=date('Y-d-m', strtotime($_POST['ch_DateOfBirth'][$i]));
  $sql6="INSERT into  tbl_children (Emp_ID, Ch_Name, Ch_Bdate) values ('".$emp_id."', '".$child_name[$i]."', '".$child_bday."') ";
  $dbcon->query($sql6);
}