我怎样才能压缩这个简单的“if”行代码？(How can I condense this simple “if” line of code?)

我怎样才能压缩这个简单的“if”行代码？(How can I condense this simple “if” line of code?)

我在程序中有一行代码，用于检查数字是否可以被多个数字整除。

然而，我目前的方式是非常低效和丑陋的。

它目前看起来像：

if(x % 1 == 0 and x % 2 == 0 and x % 3 == 0)等等。 我希望有人能教我如何取长补短，并帮助我用更有意义的东西取而代之，而不是像下面这样：

if(x % a[1,2,3] == 0)

这是可能的，如果有的话，任何人都可以帮助我吗？

编辑：x％1 == 0，x％2 == 0等等。不是完整的等式。 我正在检查远远超过％1,2和3.我正在寻找一个解决方案，可以说.. 1到15.这就是为什么我不使用x％6。

I have a line of code in my program that checks if a number is divisible by several numbers.

However, the way I currently have it is extremely inefficient and ugly.

It currently looks like:

if(x % 1 == 0 and x % 2 == 0 and x % 3 == 0) and so forth for several other numbers. I was hoping someone could teach me how I could take out the long and chain and help me replace it with something that makes more sense so instead it will look like:

if(x % a[1,2,3] == 0)

Is this possible and if so can anyone please help me?

EDIT: The x % 1 == 0, x % 2 == 0, etc.. Is not the full equation. I am checking far more than % 1,2, and 3. I am looking for a solution that can take say.. 1 through 15. That is why I am not using x % 6.

最满意答案

if all(x % k == 0 for k in [1, 2, 3]): print 'yay' if all(x % k == 0 for k in [1, 2, 3]): print 'yay'