迭代python中的嵌套元组(iterating through a nested tuple in python)

迭代python中的嵌套元组(iterating through a nested tuple in python)

我是python的新手，并试图弄清楚如何迭代嵌套元组。

这是一个元组：

x=((1,2,('a', 'b', (6,9,7)), 6,('$','@')))

我正在尝试迭代，所以我可以分别打印每个值，如：

1 2 a b 6 9 7 6 $ @

这是我的代码，请让我知道我在这里做错了什么：

x=((1,2,('a', 'b', (6,9,7)), 6,('$','@'))) f=0 for y in x: print(x[f]) f = f+1

I'm new to python and trying to figure out how to iterate through a nested tuple.

here is a tuple:

x=((1,2,('a', 'b', (6,9,7)), 6,('$','@')))

I'm trying to iterate so I can print each value separately like:

1 2 a b 6 9 7 6 $ @

Here is my code, please let me know what I'm doing wrong here:

x=((1,2,('a', 'b', (6,9,7)), 6,('$','@'))) f=0 for y in x: print(x[f]) f = f+1

最满意答案

你可以试试递归。 检查元素是否为元组，如果是，则进行递归调用，如果不是则打印它。

x=(((1,2,3,4),2,('a', 'b', (6,9,7)), 6,('$','@'))) def foo(a): for b in a: if isinstance(b,tuple): foo(b) else: print b foo(x)

输出：

1 2 3 4 2 a b 6 9 7 6 $ @

You can try with recursion. Check if element is tuple, if it is then make a recursive call to function, if it is not then print it.

x=(((1,2,3,4),2,('a', 'b', (6,9,7)), 6,('$','@'))) def foo(a): for b in a: if isinstance(b,tuple): foo(b) else: print b foo(x)

Output:

1 2 3 4 2 a b 6 9 7 6 $ @