通过Oracle SQL查询将逗号分隔的行分隔开(Split comma separated values of a column in row, through Oracle SQL query)
我有一个如下表格:
------------- ID | NAME ------------- 1001 | A,B,C 1002 | D,E,F 1003 | C,E,G -------------我希望这些值显示为:
------------- ID | NAME ------------- 1001 | A 1001 | B 1001 | C 1002 | D 1002 | E 1002 | F 1003 | C 1003 | E 1003 | G -------------我试着做:
select split('A,B,C,D,E,F', ',') from dual; -- WILL RETURN COLLECTION select column_value from table (select split('A,B,C,D,E,F', ',') from dual); -- RETURN COLUMN_VALUEI have a table like below:
------------- ID | NAME ------------- 1001 | A,B,C 1002 | D,E,F 1003 | C,E,G -------------I want these values to be displayed as:
------------- ID | NAME ------------- 1001 | A 1001 | B 1001 | C 1002 | D 1002 | E 1002 | F 1003 | C 1003 | E 1003 | G -------------I tried doing:
select split('A,B,C,D,E,F', ',') from dual; -- WILL RETURN COLLECTION select column_value from table (select split('A,B,C,D,E,F', ',') from dual); -- RETURN COLUMN_VALUE最满意答案
尝试使用以下查询:
WITH T AS (SELECT 'A,B,C,D,E,F' STR FROM DUAL) SELECT REGEXP_SUBSTR (STR, '[^,]+', 1, LEVEL) SPLIT_VALUES FROM T CONNECT BY LEVEL <= (SELECT LENGTH (REPLACE (STR, ',', NULL)) FROM T)以下ID为查询:
WITH TAB AS (SELECT '1001' ID, 'A,B,C,D,E,F' STR FROM DUAL ) SELECT ID, REGEXP_SUBSTR (STR, '[^,]+', 1, LEVEL) SPLIT_VALUES FROM TAB CONNECT BY LEVEL <= (SELECT LENGTH (REPLACE (STR, ',', NULL)) FROM TAB);编辑:尝试使用下面的查询多个ID和多个分隔:
WITH TAB AS (SELECT '1001' ID, 'A,B,C,D,E,F' STR FROM DUAL UNION SELECT '1002' ID, 'D,E,F' STR FROM DUAL UNION SELECT '1003' ID, 'C,E,G' STR FROM DUAL ) select id, substr(STR, instr(STR, ',', 1, lvl) + 1, instr(STR, ',', 1, lvl + 1) - instr(STR, ',', 1, lvl) - 1) name from ( select ',' || STR || ',' as STR, id from TAB ), ( select level as lvl from dual connect by level <= 100 ) where lvl <= length(STR) - length(replace(STR, ',')) - 1 order by ID, NAMETry using below query:
WITH T AS (SELECT 'A,B,C,D,E,F' STR FROM DUAL) SELECT REGEXP_SUBSTR (STR, '[^,]+', 1, LEVEL) SPLIT_VALUES FROM T CONNECT BY LEVEL <= (SELECT LENGTH (REPLACE (STR, ',', NULL)) FROM T)Below Query with ID:
WITH TAB AS (SELECT '1001' ID, 'A,B,C,D,E,F' STR FROM DUAL ) SELECT ID, REGEXP_SUBSTR (STR, '[^,]+', 1, LEVEL) SPLIT_VALUES FROM TAB CONNECT BY LEVEL <= (SELECT LENGTH (REPLACE (STR, ',', NULL)) FROM TAB);EDIT: Try using below query for multiple IDs and multiple separation:
WITH TAB AS (SELECT '1001' ID, 'A,B,C,D,E,F' STR FROM DUAL UNION SELECT '1002' ID, 'D,E,F' STR FROM DUAL UNION SELECT '1003' ID, 'C,E,G' STR FROM DUAL ) select id, substr(STR, instr(STR, ',', 1, lvl) + 1, instr(STR, ',', 1, lvl + 1) - instr(STR, ',', 1, lvl) - 1) name from ( select ',' || STR || ',' as STR, id from TAB ), ( select level as lvl from dual connect by level <= 100 ) where lvl <= length(STR) - length(replace(STR, ',')) - 1 order by ID, NAME更多推荐
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