在php中的单引号之间发送参数(send parameters between single quotes in php)

在php中的单引号之间发送参数(send parameters between single quotes in php) <?php $c ='<img src="assets/img/share_fb.jpg" onclick="javascript:fbShare('.$data0["link"].','.$data0["title"].','.$data0["podcast"].','.$data0["image"].')" title="Facebook">'; ?>

如何在单引号之间发送每个值？

例如：

javascript:fbShare('www.123.com','page title','text','img/image1.jpg'); <?php $c ='<img src="assets/img/share_fb.jpg" onclick="javascript:fbShare('.$data0["link"].','.$data0["title"].','.$data0["podcast"].','.$data0["image"].')" title="Facebook">'; ?>

How can I send each value between single quotes?

Ex:

javascript:fbShare('www.123.com','page title','text','img/image1.jpg');

最满意答案

您只需要在变量的任一侧引用单引号。

<?php $c ='<img src="assets/img/share_fb.jpg" onclick="javascript:fbShare(\''.$data0["link"].'\',\''.$data0["title"].'\',\''.$data0["podcast"].'\',\''.$data0["image"].'\')" title="Facebook">'; ?>

You just need quoted single quotes either side of your variables.

<?php $c ='<img src="assets/img/share_fb.jpg" onclick="javascript:fbShare(\''.$data0["link"].'\',\''.$data0["title"].'\',\''.$data0["podcast"].'\',\''.$data0["image"].'\')" title="Facebook">'; ?>