如果我有一个C ++函数/方法,例如:
getSound(Animal a){ a.printSound(); }然后传递一个Dog对象,它扩展了Animal类,但是覆盖了Animal的printSound()方法,有没有办法在getSound()中使用Dog的getSound() ?
我已经尝试在Animal类定义虚拟中创建printSound() ,但我仍然得到原始printSound()的输出。
提前致谢。
If I have a C++ function/method, for example:
getSound(Animal a){ a.printSound(); }and then pass it a Dog object that extends the class Animal but overrides Animal's printSound() method, is there a way of using Dog's printSound() within getSound()?
I have tried making printSound() in the Animal class definition virtual, but I am still getting the output of the original printSound().
Thanks in advance.
最满意答案
使printSound虚拟是正确的。 更改getSound的签名以获取Animal&或const Animal& 。 通过以Animal为价值,你正在从你的Dog身上构建一个新的Animal ,这只是一个Animal ,而不是一只Dog 。
Making printSound virtual was correct. Change the signature of getSound to take a Animal& or const Animal&. By taking an Animal by value you are constructing a new Animal from your Dog, and that's just an Animal, not a Dog.
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