我正在尝试malloc一个3d数组然后初始化它,如下所示,问题是,我得到一个警告说我正在尝试'取消引用下一行中的未定义指针值': Parque->matriz[i][j][p]='@';
任何帮助将不胜感激。
我的代码如下:
parque *Parque; Parque = (parque *) malloc(sizeof(parque)); Parque->matriz = (char***)malloc(x * sizeof(char **)); for (i = 0; i < x; i++) { Parque->matriz[i] = (char**)malloc(y * sizeof(char*)); for (j = 0; j < y; j++) { Parque->matriz[i][j] = (char*)malloc(z*sizeof(char)); } } for (p=0; p<z; p++) { for (j=y-1;j>=0; j--) { for (i=0; i<x; i++) { Parque->matriz[i][j][p]='@'; } } }这是struct parque的定义:
struct _parque{ int dimx; int dimy; int pisos; int entradas; int acessos; int nodes; char ***matriz; int capacidade; int lugares_ocupados; }; typedef struct _parque parque;I'm trying to malloc a 3d array and then initialise it, as follows, the problem is, I get a warning saying I'm trying to 'dereference an undefined pointer value' in the following line: Parque->matriz[i][j][p]='@';
Any help will be greatly appreciated.
My code is as follows:
parque *Parque; Parque = (parque *) malloc(sizeof(parque)); Parque->matriz = (char***)malloc(x * sizeof(char **)); for (i = 0; i < x; i++) { Parque->matriz[i] = (char**)malloc(y * sizeof(char*)); for (j = 0; j < y; j++) { Parque->matriz[i][j] = (char*)malloc(z*sizeof(char)); } } for (p=0; p<z; p++) { for (j=y-1;j>=0; j--) { for (i=0; i<x; i++) { Parque->matriz[i][j][p]='@'; } } }and this is the definition of struct parque:
struct _parque{ int dimx; int dimy; int pisos; int entradas; int acessos; int nodes; char ***matriz; int capacidade; int lugares_ocupados; }; typedef struct _parque parque;最满意答案
你的代码似乎是正确的,尽管你有一种有趣的方法来迭代索引。 也许你的编译器感到困惑。 请尝试:
for (i = 0; i < x; i++) { Parque->matriz[i] = (char**)malloc(y * sizeof(char*)); for (j = 0; j < y; j++) { Parque->matriz[i][j] = (char*)malloc(z*sizeof(char)); for (p = 0; p < z; p++) { Parque->matriz[i][j][p]='@'; } } }这在语义上等同于第二组嵌套循环。
Your code seems correct, though you have a funny way of iterating over the indices. Maybe your compiler got confused. Please try:
for (i = 0; i < x; i++) { Parque->matriz[i] = (char**)malloc(y * sizeof(char*)); for (j = 0; j < y; j++) { Parque->matriz[i][j] = (char*)malloc(z*sizeof(char)); for (p = 0; p < z; p++) { Parque->matriz[i][j][p]='@'; } } }This would be semantically equivalent to you second set of nested loops.
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