我在动态填充jQuery Mobile中的选择菜单时遇到了问题。
当我添加选项时,初始值不显示,我只是得到一个空行。 这些值在那里并且在点击菜单时可以选择,但它只是初始视图。 当我将菜单硬编码到页面时,它工作正常。 我会认为这是因为我最初有一个空的下拉列表,因为它应该和附加时显示,视图不知道更新,所以不断显示一个空行。 无论如何,我可以强制视图更新后,我已经附加? 我试过.trigger("create")但这没有做任何事情。
这是一个显示我的意思的屏幕。 “位置”下拉列表是我遇到的问题,“测试”是我用硬编码来显示我想实现的目标。
这里是HTML:
<label for="location" class="select">Location</label> <select name="location" id="location"></select> <label for="test" class="select">Test DD</label> <select name="test" id="test"> <option value="test1">Test 1</option> <option value="test2">Test 2</option> <option value="test3">Test 3</option> <option value="test4">Test 4</option> <option value="test5">Test 5</option> </select>这里是JS:
tx.executeSql('SELECT * FROM locations WHERE lDeleted != 1', [], function(tx,results){ var len = results.rows.length; for (var i=0; i<len; i++){ $('#location').append('<option value="'+results.rows.item(i).ID+ '" class="dropDownBlk">'+results.rows.item(i).lTitle+'</option>'); } $('#location').append('<option value="0">Add new location...</option>') }, errorCB );I am having issues with dynamically populating a select menu in jQuery mobile.
When I append the options, the initial value isn't shown and I just get a blank line. The values are there and selectable when clicking on the menu, but it is just the initial view. It works fine when I hardcode the menu into the page. I would assume it is because I initially have an empty dropdown which is showing as it should and when appending, the view doesn't know to update so keeps showing an empty line. Is there anyway I can force the view to update after I have appended? I've tried .trigger("create") but this does nothing.
Here is a screen showing what I mean. The "location" dropdown is the one I am having issue with and the "test" one is one I have hard coded to show what I am trying to achieve.
Here's the HTML:
<label for="location" class="select">Location</label> <select name="location" id="location"></select> <label for="test" class="select">Test DD</label> <select name="test" id="test"> <option value="test1">Test 1</option> <option value="test2">Test 2</option> <option value="test3">Test 3</option> <option value="test4">Test 4</option> <option value="test5">Test 5</option> </select>And here's the JS:
tx.executeSql('SELECT * FROM locations WHERE lDeleted != 1', [], function(tx,results){ var len = results.rows.length; for (var i=0; i<len; i++){ $('#location').append('<option value="'+results.rows.item(i).ID+ '" class="dropDownBlk">'+results.rows.item(i).lTitle+'</option>'); } $('#location').append('<option value="0">Add new location...</option>') }, errorCB );最满意答案
这已经成功了:
$("#location").trigger("change");This has done the trick:
$("#location").trigger("change");更多推荐
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