从eclipse插件中的jar文件中读取类名(read class names from a jar file in eclipse plug

从eclipse插件中的jar文件中读取类名(read class names from a jar file in eclipse plug-in)

我需要从jar文件（OSGified）中读取类名（只是简单名称）。 我已将jar文件放在lib文件夹中，并将其添加到类路径中。 这是我写的代码：

public void loadClassName() throws IOException { JarFile jf = new JarFile("/lib/xxxx-1.0.0.jar"); List<String> list = new ArrayList<String>(); for (JarEntry entry : Collections.list(jf.entries())) { if (entry.getName().endsWith(".class")) { String className = entry.getName().replace("/", ".").replace(".class", ""); list.add(className); } } }

不知何故，我在构造jarfile对象时遇到了Filenotfound异常。有人能告诉我们应该如何给JarFile构造函数提供jar路径吗？

I need to read class names(just the simple name) from a jar file(OSGified). I've placed the jar file in the lib folder and it's added to class path. Here is the code I've written:

public void loadClassName() throws IOException { JarFile jf = new JarFile("/lib/xxxx-1.0.0.jar"); List<String> list = new ArrayList<String>(); for (JarEntry entry : Collections.list(jf.entries())) { if (entry.getName().endsWith(".class")) { String className = entry.getName().replace("/", ".").replace(".class", ""); list.add(className); } } }

Somehow, I"m getting Filenotfound exception while constructing the jarfile object. Can somebody let me know how we should give the jar path to the JarFile constructor ?

最满意答案

试试这个： JarFile jf = new JarFile("lib/xxxx-1.0.0.jar");

Thanks to the user @Perception. His answer has worked flawlessly.

This is the working code:

final InputStream jarStream = Thread.currentThread().getContextClassLoader().getResourceAsStream("lib/xxxxx-1.0.0.jar"); JarInputStream jfs = new JarInputStream(jarStream); List<String> list = new ArrayList<String>(); JarEntry je = null; while (true) { je = jfs.getNextJarEntry(); if (je == null) { break; } if (je.getName().endsWith(".class")) { String className = je.getName().replace("/", ".").replace(".class", ""); list.add(className); } }