列表上的连锁操作(Chainable operations on lists)
我想要做类似的事情
list = [6,4,1,10,8].sort().reverse()要么
zip([x**2 for x in xrange(5)], [x**3 for x in xrange(5)].reverse()])但这不起作用,因为列表中的方法不会返回原始对象,所以它们不可链接。
我是否必须使用多行执行此操作,或者是否有一些很酷的函数式编程魔法,我可以在python中通过一行来实现这一点?
I want to do something like
list = [6,4,1,10,8].sort().reverse()or
zip([x**2 for x in xrange(5)], [x**3 for x in xrange(5)].reverse()])but this doesn't work because methods on list doesn't return the original object, so they're not chainable.
Do I have to do this using multiple lines or is there some cool functional programming magic I can do in python to achieve this in one line?
最满意答案
你想sorted()和reversed() 。
You want sorted() and reversed().
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