摆脱字符串中的扩展ASCII字符(Getting rid of Extended ASCII characters in a string)

摆脱字符串中的扩展ASCII字符(Getting rid of Extended ASCII characters in a string)

我有一个扩展名为ASCII char的字符串，我试图将其删除。 如何在字符串中找到它并从字符串中删除它： 1ÿ1ÿ0ÿÿÿ ？

字节数组，buffer = {49,0,255,255,49,0,255,255,48,0,255,255,255,255}

我正在使用C＃，字符串是由像这样的字节数组形成的： temp.Add(System.Text.Encoding.ASCII.GetString(buffer));

然后，temp中的第一项是"1\0??1\0??0\0????"

我想从字符串中删除非ASCII值，或者更好的是缓冲区。

I have a string that has extended ASCII char ÿ in it and I am trying to delete it. How do I find it in a string and delete it from a string like this: 1ÿ1ÿ0ÿÿÿ?

The byte array, buffer = { 49, 0, 255, 255, 49, 0, 255, 255, 48, 0, 255, 255, 255, 255 }

I am using C# and the string was formed from a byte array like so: temp.Add(System.Text.Encoding.ASCII.GetString(buffer));

Then, the first item in temp is "1\0??1\0??0\0????"

I would like to remove the non-ASCII values from the string, or better yet the buffer.

最满意答案

要在创建字符串之前从缓冲区中删除字符：

byte[] buffer = new byte[] { 49, 0, 255, 255, 49, 0, 255, 255, 48, 0, 255, 255, 255, 255 } var cleanBuffer = buffer.Where((b) => b < 128).ToArray(); string temp = Encoding.ASCII.GetString(cleanBuffer);

如果你试图将它转换为字符串，然后删除有问题的字符，你不能说出合法的区别? 因为转换失败而放置在那里的角色和角色。 也就是说，如果你的缓冲区包含：

{ 63, 63, 49, 0, 255, 255, 49, 0, 255, 255, 48, 0, 255, 255, 255, 255 }

然后生成的字符串将以??1\0??开头。 。 前两个问号是合法的，但最后两个是转换失败的结果。

To remove the characters from the buffer before creating the string:

byte[] buffer = new byte[] { 49, 0, 255, 255, 49, 0, 255, 255, 48, 0, 255, 255, 255, 255 } var cleanBuffer = buffer.Where((b) => b < 128).ToArray(); string temp = Encoding.ASCII.GetString(cleanBuffer);

If you try to convert it to a string and then remove the offending characters, you can't tell the difference between a legitimate ? character and one that was placed there because conversion failed. That is, if your buffer contained:

{ 63, 63, 49, 0, 255, 255, 49, 0, 255, 255, 48, 0, 255, 255, 255, 255 }

Then the resulting string would start with ??1\0??. The first two question marks are legitimate, but the last two are the result of conversion failure.