无法弄清楚Infile和输出的Python语法[重复](Cant figure out Python Syntax for Infile and Output [duplicate])

无法弄清楚Infile和输出的Python语法[重复](Cant figure out Python Syntax for Infile and Output [duplicate])

这个问题在这里已有答案：

使用Python 3打印语法错误[重复] 9个答案

我有一个python脚本但我不知道如何使用它。 脚本看起来像这样

def usage(): print "usage : ./ssl-patch <apk file>" def unzip_apk(infile, output): zfile = zipfile.ZipFile(infile, 'r') zfile.extractall(output) zfile.close() def zip_to_apk(indir, output): outapk = zipfile.ZipFile(output, 'w') for (path, dirs, files) in os.walk(indir): zipath = path[len("./" + output):] for filename in files: outapk.write(os.path.join(path, filename), os.path.join(zipath, filename), zipfile.ZIP_DEFLATED) outapk.close() def escape_dollar(string): return(re.sub('\$','\\$',string))

我把所有的文件放在一个文件夹然后用cd定位到它然后写了nameOfScript.py fileName.apk我也尝试了很多其他的方法来编写它但是无法弄明白。

但我得到了错误

print "usage : ./ssl-path <apk file>" ^ SyntaxError: invalid syntax

谢谢 ：）

This question already has an answer here:

Syntax error on print with Python 3 [duplicate] 3 answers

I have a python script but I am not sure how I can use it. The script looks like this

def usage(): print "usage : ./ssl-patch <apk file>" def unzip_apk(infile, output): zfile = zipfile.ZipFile(infile, 'r') zfile.extractall(output) zfile.close() def zip_to_apk(indir, output): outapk = zipfile.ZipFile(output, 'w') for (path, dirs, files) in os.walk(indir): zipath = path[len("./" + output):] for filename in files: outapk.write(os.path.join(path, filename), os.path.join(zipath, filename), zipfile.ZIP_DEFLATED) outapk.close() def escape_dollar(string): return(re.sub('\$','\\$',string))

I put all the files in one folder then located to it with cd and then wrote nameOfScript.py fileName.apk I have also tried many other ways to write it but cant figure it out.

but I get the error

print "usage : ./ssl-path <apk file>" ^ SyntaxError: invalid syntax

Thanks :)

最满意答案

欢迎来到SO。

该脚本缺少一个主要部分，它只包含函数定义（从def开始）。

可以使用python [name_of_script] [command-line-parameters]调用包含主要部分的脚本（使用if __name__ == '__main__':或只是在函数定义之外使用语句）。

希望有所帮助:)

Welcome to SO.

The script lacks a main section, it only consists of function definitions (starting with def).

A script that includes a main part (either using if __name__ == '__main__': or just having statements outside of function definitions) can be invoked with python [name_of_script] [command-line-parameters].

Hope that helps :)