在javamail中添加setFrom时未处理的异常类型MessagingException(unhandled exception type MessagingException when addi

在javamail中添加setFrom时未处理的异常类型MessagingException(unhandled exception type MessagingException when adding setFrom in javamail) MimeMessage msg = new MimeMessage(session); msg.setFrom(new InternetAddress("xyz@example.com")); msg.addRecipient(Message.RecipientType.TO, new InternetAddress("abcd@example.com"));

在最后两行中获取unhandled exception type MessagingException 。

Eclipse建议我用try catch块覆盖它们。但是当我尝试在互联网上搜索时，他们正在使用这两个语句而没有任何尝试catch块。 所以我想我做错了什么。 怎么解决这个？

MimeMessage msg = new MimeMessage(session); msg.setFrom(new InternetAddress("xyz@example.com")); msg.addRecipient(Message.RecipientType.TO, new InternetAddress("abcd@example.com"));

Getting error in last two lines that unhandled exception type MessagingException.

Eclipse suggests me to cover them with a try catch block.But when i tried to search in internet they are using these two statement without any try catch block. so i think i am doing something wrong. how to solve this?

最满意答案

你必须有可能解决它。

在代码中添加try-catch-block：

尝试{MimeMessage msg = new MimeMessage（session）; msg.setFrom（new InternetAddress（“xyz@example.com”））; msg.addRecipient（Message.RecipientType.TO，new InternetAddress（“abcd@example.com”））;

} catch（MessagingException me）{//做某事}

throws MessagingException到方法签名：

public void mymethod throws MessagingException {MimeMessage msg = new MimeMessage（session）; msg.setFrom（new InternetAddress（“xyz@example.com”））; msg.addRecipient（Message.RecipientType.TO，new InternetAddress（“abcd@example.com”））; }

You have to possibilities to solve it.

Add a try-catch- block arround your code:

try { MimeMessage msg = new MimeMessage(session); msg.setFrom(new InternetAddress("xyz@example.com")); msg.addRecipient(Message.RecipientType.TO, new InternetAddress("abcd@example.com"));

} catch (MessagingException me){ // do something }

Add throws MessagingException to the method signature:

public void mymethod throws MessagingException { MimeMessage msg = new MimeMessage(session); msg.setFrom(new InternetAddress("xyz@example.com")); msg.addRecipient(Message.RecipientType.TO, new InternetAddress("abcd@example.com")); }