选择第n个兄弟姐妹(Select the nth following sibling)

选择第n个兄弟姐妹(Select the nth following sibling)

我想知道是否有更好的解决方案，而不是改变html结构

HTML结构看起来像这样

<div class="wrap"> <div class="divider"></div> <div class="block"></div> <div class="block"></div> <div class="divider"></div> </div>

因此，在同一级别上有各种DIV，我想要做的是以不同的方式对每个第四块进行着色，直到出现分隔线，然后再重新计算。

我认为像.block:nth-child(4n)这样的东西可以做到这一点，但它实际上是基于父类而不是基于类来计算元素。

这里是JSFiddle试用。 每行中的块＃4和＃8应该有不同的颜色http://jsfiddle.net/SKgdH/3/

这就是我如何做它的工作： http : //jsfiddle.net/SKgdH/1/

我所做的就是寻找.divider的第四个兄弟，像这样.divider + .block + .block + .block + .block

它可以工作，但是，我必须在第8,12,16，...块中写入相同的内容，但不会使其自动生效。

有没有像.divider + .block:nth-sibling(4)或.divider + .block:nth-of-class(4) ？

也许你们中的一个人在不改变源代码或使用javascript的情况下就知道如何解决这个问题。

I wondered if there is a better solution than to what I found without changing the html-structure

The HTML structure looks like this

<div class="wrap"> <div class="divider"></div> <div class="block"></div> <div class="block"></div> <div class="divider"></div> </div>

So there's various DIVs on the same level, what I want to do is to color every fourth block differently, until a divider appears, then it'd have to recount.

I thought something like .block:nth-child(4n) would do the trick, but it actually counts the elements based on the parent, not based on the class.

Here's the JSFiddle to try out. Block #4 and #8 in each row should be differently colored http://jsfiddle.net/SKgdH/3/

And this is how I made it sort-of work: http://jsfiddle.net/SKgdH/1/

What I did was to look for the 4th sibling of the .divider like this .divider + .block + .block + .block + .block

It works, however, I'd have to write the same for the 8th, 12th, 16th, .. block, which doesn't make it automatic anymore.

Is there something like .divider + .block:nth-sibling(4) or .divider + .block:nth-of-class(4)?

Maybe one of you got an idea on how to solve this without changing the source code or using javascript.

最满意答案

这样的伪类不会工作，因为您期望它匹配相对于不同复合选择器的元素，而不是简单的选择器的工作方式。 例如，如果你编写了一个复杂的选择器，只有一个具有该伪类的复合选择器（并且没有同级组合器）：

.block:nth-sibling(4n)

你会期望这匹配.block:nth-child(4n) ，完全没有匹配，或者无效？

能够缩小+ .block + .block + .block + .block并以某种方式重复它会很好，但不幸的是，由于选择器语法的设计方式，这是不可能的。

您必须使用JavaScript和/或向适当的元素添加额外的类。

Such a pseudo-class would not work because you are expecting it to match elements relative to a different compound selector, which is not how simple selectors work. For example, if you wrote a complex selector that only had a single compound selector with that pseudo-class (and no sibling combinators):

.block:nth-sibling(4n)

Would you expect this to match .block:nth-child(4n), match nothing at all, or be invalid?

It'd be nice to be able to abridge + .block + .block + .block + .block and make it repeat somehow, but unfortunately due to how the selector syntax is designed, it's just not possible.

You'll have to use JavaScript and/or add extra classes to the appropriate elements instead.