有2行数据库在Google Map上显示相同的点(Have 2 rows of a database display same point on Google Map)
我正在尝试在地图上显示profFName和profLName多个值，其中单个点应显示此值。
所以，如果我有（2）pID连接到同一个标记......它应该在一个点上显示profFName和profLName 。
**现在它正在以完全相同的纬度/经度创建两个标记，因此它绘制了3个点（从数据库中看到）但如果在该位置存在多位教授则不显示（1）点**
使用Javascript
<script type="text/javascript"> //<![CDATA[ var iconBlue = new GIcon(); iconBlue.image = 'http://labs.google.com/ridefinder/images/mm_20_blue.png'; iconBlue.shadow = 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'; iconBlue.iconSize = new GSize(12, 20); iconBlue.shadowSize = new GSize(22, 20); iconBlue.iconAnchor = new GPoint(6, 20); iconBlue.infoWindowAnchor = new GPoint(5, 1); var iconRed = new GIcon(); iconRed.image = 'http://labs.google.com/ridefinder/images/mm_20_red.png'; iconRed.shadow = 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'; iconRed.iconSize = new GSize(12, 20); iconRed.shadowSize = new GSize(22, 20); iconRed.iconAnchor = new GPoint(6, 20); iconRed.infoWindowAnchor = new GPoint(5, 1); var customIcons = []; customIcons["restaurant"] = iconBlue; customIcons["bar"] = iconRed; function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(47.614495, -122.341861), 13); GDownloadUrl("phpsqlajax_genxml.php", function(data) { var xml = GXml.parse(data); var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("name"); var address = markers[i].getAttribute("address"); var profFName = markers[i].getAttribute("profFName"); var profLName = markers[i].getAttribute("profLName"); var type = markers[i].getAttribute("type"); var point = new GLatLng(parseFloat(markers[i].getAttribute("lat")), parseFloat(markers[i].getAttribute("lng"))); var marker = createMarker(point, name, address, profFName, profLName, type); map.addOverlay(marker); } }); } } function createMarker(point, name, address, profFName, profLName, type) { var marker = new GMarker(point, customIcons[type]); var html = "<b>" + name + "</b> <br/>" + address + "<br><br>" + profFName + profLName; GEvent.addListener(marker, 'click', function() { marker.openInfoWindowHtml(html); }); return marker; } //]]> </script> </head> <body onload="load()" onunload="GUnload()"> <div id="map" style="width: 110 0px; height: 500px"></div> </body>PHP
<?php require("phpsqlajax_dbinfo.php"); function parseToXML($htmlStr) { $xmlStr=str_replace('<','<',$htmlStr); $xmlStr=str_replace('>','>',$xmlStr); $xmlStr=str_replace('"','"',$xmlStr); $xmlStr=str_replace("'",''',$xmlStr); $xmlStr=str_replace("&",'&',$xmlStr); return $xmlStr; } // Opens a connection to a MySQL server $connection=mysql_connect ($host, $username, $password); if (!$connection) { die('Not connected : ' . mysql_error()); } // Set the active MySQL database $db_selected = mysql_select_db($database, $connection); if (!$db_selected) { die ('Can\'t use db : ' . mysql_error()); } // Select all the rows in the markers table $query = "SELECT * FROM markers M, professor P WHERE P.id = M.id;"; if($row = mysql_fetch_array($result)) { do { echo $row; } while($row = mysql_fetch_array($result)); } else { die('No results.'); } header("Content-type: text/xml"); // Start XML file, echo parent node echo '<markers>'; // Iterate through the rows, printing XML nodes for each while ($row = @mysql_fetch_assoc($result)){ // ADD TO XML DOCUMENT NODE echo '<marker '; echo 'name="' . parseToXML($row['name']) . '" '; echo 'address="' . parseToXML($row['address']) . '" '; echo 'profFName="' . parseToXML($row['profFName']) . '" '; echo 'profLName="' . parseToXML($row['profLName']) . '" '; echo 'lat="' . $row['lat'] . '" '; echo 'lng="' . $row['lng'] . '" '; echo 'type="' . $row['type'] . '" '; echo '/>'; } // End XML file echo '</markers>'; ?>I'm trying to have multiple values for profFName and profLName display on a map where a single point should display this value.
So, if I have (2) pID connected to the same marker... it should display the profFName and profLName on one point.
** Right now it is creating two markers at the exact same lat/longitude so it is plotting 3 points (as seen from the database) but it doesnt show (1) point if multiple professors exist at that location **
Javascript
<script type="text/javascript"> //<![CDATA[ var iconBlue = new GIcon(); iconBlue.image = 'http://labs.google.com/ridefinder/images/mm_20_blue.png'; iconBlue.shadow = 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'; iconBlue.iconSize = new GSize(12, 20); iconBlue.shadowSize = new GSize(22, 20); iconBlue.iconAnchor = new GPoint(6, 20); iconBlue.infoWindowAnchor = new GPoint(5, 1); var iconRed = new GIcon(); iconRed.image = 'http://labs.google.com/ridefinder/images/mm_20_red.png'; iconRed.shadow = 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'; iconRed.iconSize = new GSize(12, 20); iconRed.shadowSize = new GSize(22, 20); iconRed.iconAnchor = new GPoint(6, 20); iconRed.infoWindowAnchor = new GPoint(5, 1); var customIcons = []; customIcons["restaurant"] = iconBlue; customIcons["bar"] = iconRed; function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(47.614495, -122.341861), 13); GDownloadUrl("phpsqlajax_genxml.php", function(data) { var xml = GXml.parse(data); var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("name"); var address = markers[i].getAttribute("address"); var profFName = markers[i].getAttribute("profFName"); var profLName = markers[i].getAttribute("profLName"); var type = markers[i].getAttribute("type"); var point = new GLatLng(parseFloat(markers[i].getAttribute("lat")), parseFloat(markers[i].getAttribute("lng"))); var marker = createMarker(point, name, address, profFName, profLName, type); map.addOverlay(marker); } }); } } function createMarker(point, name, address, profFName, profLName, type) { var marker = new GMarker(point, customIcons[type]); var html = "<b>" + name + "</b> <br/>" + address + "<br><br>" + profFName + profLName; GEvent.addListener(marker, 'click', function() { marker.openInfoWindowHtml(html); }); return marker; } //]]> </script> </head> <body onload="load()" onunload="GUnload()"> <div id="map" style="width: 110 0px; height: 500px"></div> </body>PHP
<?php require("phpsqlajax_dbinfo.php"); function parseToXML($htmlStr) { $xmlStr=str_replace('<','<',$htmlStr); $xmlStr=str_replace('>','>',$xmlStr); $xmlStr=str_replace('"','"',$xmlStr); $xmlStr=str_replace("'",''',$xmlStr); $xmlStr=str_replace("&",'&',$xmlStr); return $xmlStr; } // Opens a connection to a MySQL server $connection=mysql_connect ($host, $username, $password); if (!$connection) { die('Not connected : ' . mysql_error()); } // Set the active MySQL database $db_selected = mysql_select_db($database, $connection); if (!$db_selected) { die ('Can\'t use db : ' . mysql_error()); } // Select all the rows in the markers table $query = "SELECT * FROM markers M, professor P WHERE P.id = M.id;"; if($row = mysql_fetch_array($result)) { do { echo $row; } while($row = mysql_fetch_array($result)); } else { die('No results.'); } header("Content-type: text/xml"); // Start XML file, echo parent node echo '<markers>'; // Iterate through the rows, printing XML nodes for each while ($row = @mysql_fetch_assoc($result)){ // ADD TO XML DOCUMENT NODE echo '<marker '; echo 'name="' . parseToXML($row['name']) . '" '; echo 'address="' . parseToXML($row['address']) . '" '; echo 'profFName="' . parseToXML($row['profFName']) . '" '; echo 'profLName="' . parseToXML($row['profLName']) . '" '; echo 'lat="' . $row['lat'] . '" '; echo 'lng="' . $row['lng'] . '" '; echo 'type="' . $row['type'] . '" '; echo '/>'; } // End XML file echo '</markers>'; ?>最满意答案
快速解决方案
使用GROUP_CONCAT函数我可以将多个MySQL行连接到一个字段中吗？ 仅显示标记并为每个标记添加属性ID。 单击标记时从数据库中选择并连接已接收的行 创建添加标记的关联数组{id：marker reference}。 在函数createMarker中检查此数组，如果标记id已经存在，则在数组中使用传入函数的标记连接html。 如果没有将标记添加到数组。Quick solutions:
Use GROUP_CONCAT function Can I concatenate multiple MySQL rows into one field? display only markers and add attribute id to each marker. When you click on marker select from database and concat received rows Create associative array of added markers {id: marker reference}. In function createMarker check this array and if marker id is already present, concate html of marker in array with marker passed in function. If not add marker to array.更多推荐
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