如何用Java验证电话号码(美国格式)?(How to validate phone number(US format) in Java?)
我只是想知道我在哪里错了:
import java.io.*; class Tokens{ public static void main(String[] args) { //String[] result = "this is a test".split(""); String[] result = "4543 6546 6556".split(""); boolean flag= true; String num[] = {"0","1","2","3","4","5","6","7","8","9"}; String specialChars[] = {"-","@","#","*"," "}; for (int x=1; x<result.length; x++) { for (int y=0; y<num.length; y++) { if ((result[x].equals(num[y]))) { flag = false; continue; } else { flag = true; } if (flag == true) break; } if (flag == false) break; } System.out.println(flag); } }I just want to know where am i wrong here:
import java.io.*; class Tokens{ public static void main(String[] args) { //String[] result = "this is a test".split(""); String[] result = "4543 6546 6556".split(""); boolean flag= true; String num[] = {"0","1","2","3","4","5","6","7","8","9"}; String specialChars[] = {"-","@","#","*"," "}; for (int x=1; x<result.length; x++) { for (int y=0; y<num.length; y++) { if ((result[x].equals(num[y]))) { flag = false; continue; } else { flag = true; } if (flag == true) break; } if (flag == false) break; } System.out.println(flag); } }更多推荐
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