python正则表达式re.search（r“（[az] + [AZ] + [0

python正则表达式re.search（r“（[az] + [AZ] + [0-9] +）”，密码）(python regular expression re.search(r“([a-z]+[A-Z]+[0-9]+)”, password))

python 2.7

>>>import re >>>password="ULFFunH8ni" >>>re.search(r"([a-z]+[A-Z]+[0-9]+)", password) <_sre.SRE_Match object at 0x7ff5ffd075d0>

可以匹配但什么时候

>>>password="Fa11con77YES" >>>re.search(r"([a-z]+[A-Z]+[0-9]+)", password) >>>

无法比拟，我不知道为什么，能有人帮帮我吗？ 谢谢！

python 2.7

>>>import re >>>password="ULFFunH8ni" >>>re.search(r"([a-z]+[A-Z]+[0-9]+)", password) <_sre.SRE_Match object at 0x7ff5ffd075d0>

can match but when

>>>password="Fa11con77YES" >>>re.search(r"([a-z]+[A-Z]+[0-9]+)", password) >>>

can't match, I don't know why, can someone help me? thanks!

最满意答案

如果您要确保密码中至少有一个（较低，较高，数字），则需要单独检查：

low = re.search(r"[a-z]", password) up = re.search(r"[A-Z]", password) num = re.search(r"[0-9]", password) has_all = all((low, up, num))

基本正则表达式是特定于订单的。 另一种方法是使用前瞻（如果你的正则表达式支持它）：

re.search(r"(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])")

然而，这可能不如仅仅独立地执行每个检查。

If you're trying to ensure that the password has at least one of each (lower, upper, number) then you need to do separate checks:

low = re.search(r"[a-z]", password) up = re.search(r"[A-Z]", password) num = re.search(r"[0-9]", password) has_all = all((low, up, num))

Basic regexes are order-specific. Another way of doing this would be to use lookaheads (if your regex flavor supports it):

re.search(r"(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])")

However this may be less efficient than just doing each of the checks independently.