根据模型属性值Yii2更改Gridview中的按钮操作(Change the button action in Gridview based on a model attribute value Yi

我用CRUD生成器生成了一个简单的应用程序......

在“视图”页面中，有一个操作列，其中包含一些按钮，如视图，更新，删除....

我想要的只是创建一个状态按钮....

如果状态为非活动状态，它应该询问我并将状态更改为活动状态，反之亦然这是我的代码：

'suspend' => function($url, $model) { 
    return Html::a(
        '<span class="btn btn-xs btn-danger icon-remove bigger-80"style="margin-left:5px;"></span>',
        $url,
        ['title' => Yii::t('app', 'Inactivate')]
    );
},
'activate' => function($url, $model) {
    return Html::a(
        '<span class="btn btn-xs btn-success icon-ok bigger-80"style="margin-left:5px;"></span>',
        $url,
        ['title' => Yii::t('app', 'Activate')]
    );
},
I generated a simple application by CRUD generator...
 
In the View page there is a action column assigned with some buttons like view, update, delete....
 
all I want is to create a status button....
 
If the status is inactive it should ask me and change the status into active and vice versa This is my code:
 
'suspend' => function($url, $model) { 
    return Html::a(
        '<span class="btn btn-xs btn-danger icon-remove bigger-80"style="margin-left:5px;"></span>',
        $url,
        ['title' => Yii::t('app', 'Inactivate')]
    );
},
'activate' => function($url, $model) {
    return Html::a(
        '<span class="btn btn-xs btn-success icon-ok bigger-80"style="margin-left:5px;"></span>',
        $url,
        ['title' => Yii::t('app', 'Activate')]
    );
},

                
最满意答案
                
                    
                        
 试试这个...... 
 
        [
          'class' => 'yii\grid\ActionColumn',
          'template' => '{activate}{deactivate}',
          'buttons' => [
            'activate' => function ($url, $model) {
            if($model->status==1)
                return Html::a('<span class="glyphicon glyphicon-eye-open"></span>', $url, [
                            'title' => Yii::t('app', 'Activate'),
                ]);
            },
            'deactivate' => function ($url, $model) {
            if($model->status==0)
                return Html::a('<span class="glyphicon glyphicon-eye-open"></span>', $url, [
                            'title' => Yii::t('app', 'Deactivate'),
                ]);
            },

          ],
          'urlCreator' => function ($action, $model, $key, $index) {
            if ($action === 'acivate') {
                $url =Url::toRoute(['controller/activate', 'id' => $model->id]);
                return $url;
            }
           if ($action === 'deactivate') {
                $url =Url::toRoute(['controller/deactivate', 'id' => $model->id]);
                return $url;
            }

          }
         ],
 
 你需要包括使用yii\helpers\Url; 在你看来 
Try with this..
 
        [
          'class' => 'yii\grid\ActionColumn',
          'template' => '{activate}{deactivate}',
          'buttons' => [
            'activate' => function ($url, $model) {
            if($model->status==1)
                return Html::a('<span class="glyphicon glyphicon-eye-open"></span>', $url, [
                            'title' => Yii::t('app', 'Activate'),
                ]);
            },
            'deactivate' => function ($url, $model) {
            if($model->status==0)
                return Html::a('<span class="glyphicon glyphicon-eye-open"></span>', $url, [
                            'title' => Yii::t('app', 'Deactivate'),
                ]);
            },

          ],
          'urlCreator' => function ($action, $model, $key, $index) {
            if ($action === 'acivate') {
                $url =Url::toRoute(['controller/activate', 'id' => $model->id]);
                return $url;
            }
           if ($action === 'deactivate') {
                $url =Url::toRoute(['controller/deactivate', 'id' => $model->id]);
                return $url;
            }

          }
         ],
 
You need to include use yii\helpers\Url; in your view