在inno设置中运行InstallUtil {app} /file.exe(running InstallUtil {app}/file.exe in inno setup)

在inno设置中运行InstallUtil {app} /file.exe(running InstallUtil {app}/file.exe in inno setup)

我想将服务文件复制到{app}目录，然后将其用作InstallUtil.exe中的参数。

这是我的代码的一部分：

[Files] Source: WCFService.exe; DestDir: {app} Source: WCFService.exe.config; DestDir: {app} [Run] Filename: {dotnet40}\InstallUtil.exe; Parameters: {app}\WCFService.exe

此代码不起作用（但文件正确复制到{app}目录中）。 但是，如果我使用这样的东西：

[Files] Source: WCFService.exe; DestDir: {src} Source: WCFService.exe.config; DestDir: {src} [Run] Filename: {dotnet40}\InstallUtil.exe; Parameters: WCFService.exe

它工作正常。 有谁知道发生了什么？ 我必须使用inno设置。

I want to copy service files to {app} directory and then use this as a parameter in InstallUtil.exe.

Here's some part of my code :

[Files] Source: WCFService.exe; DestDir: {app} Source: WCFService.exe.config; DestDir: {app} [Run] Filename: {dotnet40}\InstallUtil.exe; Parameters: {app}\WCFService.exe

This code doesn't work (but the files are copied into {app} directory correctly). However, if I use something like this :

[Files] Source: WCFService.exe; DestDir: {src} Source: WCFService.exe.config; DestDir: {src} [Run] Filename: {dotnet40}\InstallUtil.exe; Parameters: WCFService.exe

it works correctly. Does anyone know what's going on? I have to use inno setup.

最满意答案

在这种情况下，您可以尝试在[Run]部分中将WorkingDir参数设置为{app} 。 喜欢这个：

[Run] Filename: "{dotnet40}\InstallUtil.exe"; WorkingDir: "{app}"; Parameters: "WCFService.exe"

In this case you could try to set WorkingDir parameter to {app} in the [Run] section. Like this:

[Run] Filename: "{dotnet40}\InstallUtil.exe"; WorkingDir: "{app}"; Parameters: "WCFService.exe"