将原始XML添加到使用libxml

将原始XML添加到使用libxml-ruby构建的XML文档中(Add raw XML into XML document built with libxml-ruby)

使用KML（当然是XML），我有很多样式 - 对于人类 - 最容易阅读和维护为原始XML。 我想将它们添加到使用libxml-ruby构建的XML文档中。

这是一个简化的例子：

require 'xml' raw_xml = <<~END <Style> <foo>bar</foo> </Style> END xml = XML::Document.new xml.root = XML::Node.new(:Document) xml.root << raw_xml xml.to_s

结果：

<?xml version="1.0" encoding="UTF-8"?> <Document>&lt;Style&gt; &lt;foo&gt;bar&lt;/foo&gt; &lt;/Style&gt; </Document>

这是预料之中的，因为<<不解析原始XML。 但是，我的问题是有没有办法正确地做到这一点并获得以下输出？

<?xml version="1.0" encoding="UTF-8"?> <Document> <Style> <foo>bar</foo> </Style> </Document>

谢谢你的提示！

Working with KMLs (which of course are XML), I have loads of styles which – for humans – are easiest to read and maintain as raw XML. I'd like to add those into a XML document being built with libxml-ruby.

Here's a simplified example:

require 'xml' raw_xml = <<~END <Style> <foo>bar</foo> </Style> END xml = XML::Document.new xml.root = XML::Node.new(:Document) xml.root << raw_xml xml.to_s

The result:

<?xml version="1.0" encoding="UTF-8"?> <Document>&lt;Style&gt; &lt;foo&gt;bar&lt;/foo&gt; &lt;/Style&gt; </Document>

That was to be expected since << does not parse the raw XML. My question, however, is there a way to do this right and get the the following output?

<?xml version="1.0" encoding="UTF-8"?> <Document> <Style> <foo>bar</foo> </Style> </Document>

Thanks for your hints!

最满意答案

xml.root是LibXML::XML::Node一个实例，它的<< ，方法用于添加节点。 不用于解析XML字符串。

要解析字符串，可以使用例如XML::Parser.string ：

xml = XML::Document.new xml.root = XML::Node.new(:Document) # Parse the string into XML::Document, then take its root node tree another_doc = XML::Parser.string(raw_xml).parse node = xml.import(another_doc.root) xml.root << node

xml.root is an instance of LibXML::XML::Node, its << ,method is for adding a node. Not for parsing XML string.

To parse a string, you can use for example XML::Parser.string:

xml = XML::Document.new xml.root = XML::Node.new(:Document) # Parse the string into XML::Document, then take its root node tree another_doc = XML::Parser.string(raw_xml).parse node = xml.import(another_doc.root) xml.root << node