使用具有超过3个以空格分隔的单词的awk打印行？(printing lines using awk which have more than 3 space-delimited words?)
我有一个包含句子行的文件。 我想要打印超过3个单词的所有行。 单词由空格分隔。
我怎么能用awk这样做？
I have a file containing lines of sentences. I want to print all lines that have more than 3 words. Words are separated by whitespace.
How could I do this with awk?
最满意答案
像这样使用awk：
awk 'NF>3' fileUse awk like this:
awk 'NF>3' file更多推荐
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