为什么我的“tel：”链接不起作用(Why are my “tel:” links not working)

为什么我的“tel：”链接不起作用(Why are my “tel:” links not working)

我有一个tableView，其中包含带有电话号码的单元格。 该应用程序不是拨打号码。 请参阅下面的代码

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { if (indexPath.section == 2) { UITableViewCell *selectedCell = [tableView cellForRowAtIndexPath:indexPath]; NSString *numberToDial = [NSString stringWithFormat:@"tel:%@", selectedCell.detailTextLabel.text]; NSLog(@"%@",numberToDial); [[UIApplication sharedApplication] openURL:[NSURL URLWithString:numberToDial]]; } }

控制台输出： 2010-03-08 01:32:30.830 AIB[1217:207] tel:01 8350098

如您所见，该数字将转到控制台，但不会拨打。 奇怪的是，如果我将最后一个语句更改为：

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:171"]];

手机拨打号码171没有任何问题

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如下所述，解决我的特定问题的方法是从电话号码中删除空格。 我实现了如下：

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { if (indexPath.section == 2) { UITableViewCell *selectedCell = [tableView cellForRowAtIndexPath:indexPath]; NSMutableString *numberToDial = [NSMutableString stringWithFormat:@"tel:%@", selectedCell.detailTextLabel.text]; [numberToDial replaceOccurrencesOfString:@" " withString:@"" options:NSLiteralSearch range:NSMakeRange(0, [numberToDial length])]; [[UIApplication sharedApplication] openURL:[NSURL URLWithString:numberToDial]]; } }

I have a tableView which has cells with phone numbers. The app is not dialing the numbers though. See the code below

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { if (indexPath.section == 2) { UITableViewCell *selectedCell = [tableView cellForRowAtIndexPath:indexPath]; NSString *numberToDial = [NSString stringWithFormat:@"tel:%@", selectedCell.detailTextLabel.text]; NSLog(@"%@",numberToDial); [[UIApplication sharedApplication] openURL:[NSURL URLWithString:numberToDial]]; } }

Console ouput: 2010-03-08 01:32:30.830 AIB[1217:207] tel:01 8350098

As you can see, the number goes to the console, but doesn't get dialled. The weird thing is, if I change the last statement to this:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:171"]];

the phone dials the number 171 without any issue

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The solution to my particular problem is, as suggested below, to remove the spaces from the phone numbers. I achieved this as follows:

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { if (indexPath.section == 2) { UITableViewCell *selectedCell = [tableView cellForRowAtIndexPath:indexPath]; NSMutableString *numberToDial = [NSMutableString stringWithFormat:@"tel:%@", selectedCell.detailTextLabel.text]; [numberToDial replaceOccurrencesOfString:@" " withString:@"" options:NSLiteralSearch range:NSMakeRange(0, [numberToDial length])]; [[UIApplication sharedApplication] openURL:[NSURL URLWithString:numberToDial]]; } }

最满意答案

您需要清理用户输入，使其成为有效的tel:// URL。 具体来说，这包括剥离：

空间 哈希（ # ） 星号（ * ）

来自iPhone开发中心 ：

为防止用户恶意重定向电话或更改电话或帐户的行为，电话应用程序支持tel方案中的大多数但不是全部特殊字符。 具体来说，如果URL包含*或＃字符，则电话应用程序不会尝试拨打相应的电话号码。

来自电话呼叫URL的URL ：

...空格绝不能用在URL中的电话号码中，因为空格字符不能在URL中使用而不能转义它。

You will need to sanitize the user input for it to be a valid tel:// URL. Specifically this includes stripping of:

Spaces Hashes (#) Asterisks(*)

From iPhone Dev Center:

To prevent users from maliciously redirecting phone calls or changing the behavior of a phone or account, the Phone application supports most, but not all, of the special characters in the tel scheme. Specifically, if a URL contains the * or # characters, the Phone application does not attempt to dial the corresponding phone number.

From URLs for URLs for Telephone Calls RFC:

...spaces MUST NOT be used in phone numbers in URLs as the space character cannot be used in URLs without escaping it.