你如何在python中正确测试divisibility [关闭](How do you correctly test for divisibility in python [closed])

你如何在python中正确测试divisibility [关闭](How do you correctly test for divisibility in python [closed])

我编写了一些代码来评估x和y之间的整数，并通过整数3和5检查可分性。这是代码。

def div_3_5(start, end): result = 0 result2 = 0 result3 = 0 while start < end: result2 = start + result result = result2 - start + 1 if result2 % 3==0 or 5==0: result3 = result3 + 1 else: result3 = result3 + 0 return result3

我只是一个初学者，但在代码中一切似乎都很好，除非我错误地使用了“或”语句或错误地检查了可分性。 这让我想到了主要问题。 任何帮助，将不胜感激。

I wrote some code to evaluate the integers between x and y and check for divisibility by the integers 3 and 5. This is the code.

def div_3_5(start, end): result = 0 result2 = 0 result3 = 0 while start < end: result2 = start + result result = result2 - start + 1 if result2 % 3==0 or 5==0: result3 = result3 + 1 else: result3 = result3 + 0 return result3

I'm just a beginner but everything seems fine in the code of course unless I have used the "or" statement incorrectly or checked for divisibility incorrectly. Which brings me to the main question. Any help would be appreciated.

最满意答案

你需要这样做：

if result2 % 3 == 0 or result2 % 5 == 0:

否则，它被解析为if (result2 % 3==0) or (5==0):这显然是错误的，因为5 != 0 。

另一个建议可能非常有用，因为您有更多数字要检查可分性：

if any(result2 % i == 0 for i in (3, 5)):

---

这是你似乎想要做的更简单的版本（Project Euler问题1）：

def div_3_5(start, end): return sum(1 for i in range(start, end+1) if i % 3 == 0 or i % 5 == 0)

或者，使用De Morgan的定律以及0是False - 值的事实：

def div_3_5(start, end): return sum(1 for i in range(start, end+1) if not (i % 3 and i % 5))

You need to do this:

if result2 % 3 == 0 or result2 % 5 == 0:

Otherwise it is parsed as if (result2 % 3==0) or (5==0):, which is clearly wrong as 5 != 0.

Another suggestion which can be quite useful as you have more numbers you want to check for divisibility:

if any(result2 % i == 0 for i in (3, 5)):

---

This is a much simpler version of what you seem to be trying to do (Project Euler problem 1):

def div_3_5(start, end): return sum(1 for i in range(start, end+1) if i % 3 == 0 or i % 5 == 0)

Or, using De Morgan's laws and the fact that 0 is a False-ish value:

def div_3_5(start, end): return sum(1 for i in range(start, end+1) if not (i % 3 and i % 5))