与包含所有元素的分区相关的功能？(Function related to partition that includes all elements?)

与包含所有元素的分区相关的功能？(Function related to partition that includes all elements?)

Clojure的partition函数的这种行为不是我所需要的：

user=> (partition 3 (range 3)) ((0 1 2)) user=> (partition 3 (range 4)) ((0 1 2)) user=> (partition 3 (range 5)) ((0 1 2)) user=> (partition 3 (range 6)) ((0 1 2) (3 4 5))

我需要包含收集的“剩余”部分，例如：

user=> (partition* 3 (range 4)) ((0 1 2) (3)) user=> (partition* 3 (range 5)) ((0 1 2) (3 4))

有没有一个标准的库函数可以实现我想要的功能？

This behavior of Clojure's partition function is not what I need:

user=> (partition 3 (range 3)) ((0 1 2)) user=> (partition 3 (range 4)) ((0 1 2)) user=> (partition 3 (range 5)) ((0 1 2)) user=> (partition 3 (range 6)) ((0 1 2) (3 4 5))

I need the 'leftover' portions of the collection to be included, e.g.:

user=> (partition* 3 (range 4)) ((0 1 2) (3)) user=> (partition* 3 (range 5)) ((0 1 2) (3 4))

Is there a standard library function that does what I want?

最满意答案

你正在寻找partition-all 。 只需在你的例子中替换它：

user> (partition-all 3 (range 4)) ((0 1 2) (3)) user> (partition-all 3 (range 5)) ((0 1 2) (3 4))

You're looking for partition-all. Just replace it in your example:

user> (partition-all 3 (range 4)) ((0 1 2) (3)) user> (partition-all 3 (range 5)) ((0 1 2) (3 4))