如何检查数组 size，N是一个自然数？(How to check array size, with N a natural number?)

如何检查数组 size，N是一个自然数？(How to check array size, with N a natural number?)

我的问题很简单。 我怎么知道声明为......的数组的大小？

array<ObjectType^, 3>

我已经看到通过下一个方式访问他们的元素：

array_var[i,j,k];

那么，我怎么知道不同尺寸的大小呢？

My question is simple. How can I know the size of an array declared as...?

array<ObjectType^, 3>

I've seen that the access to their elements is made by the next way:

array_var[i,j,k];

So, how can I know the size of the different dimensions?

最满意答案

看起来你在c ++ / cli中使用托管数组（虽然截至撰写本文时，你尚未确认这一点）。

假设您正在使用cli::array实例，您可以从其文档中看到它继承自System::Array ，并且该类的所有方法都适用。 如果您阅读该类自己的文档 ，您会发现有一个Array::GetLength(Int32)方法可以让您获得给定维度的大小（请参阅此方法的文档）。

例如，

array<ObjectType^, 3>^ array_var = gcnew array<ObjectType^, 3>(3, 4, 5);

声明一个大小为3*4*5的新3d数组。

array_var->GetLength(2)

将返回5 （因为尺寸从0开始编号，像往常一样）。 您还可以使用array_var->Rank来获取数组的维数。

It looks like you're using a managed array in c++/cli (though as of time of writing, you haven't got round to confirming this yet).

On the assumption that you are using a cli::array instance, you can see from its documentation that it inherits from System::Array, and all methods of that class are applicable. If you read that class' own documentation, you'll find that there's an Array::GetLength(Int32) method that lets you get the size of a given dimension (see that method's documentation here).

For example,

array<ObjectType^, 3>^ array_var = gcnew array<ObjectType^, 3>(3, 4, 5);

declares a new 3d array of size3*4*5.

array_var->GetLength(2)

will return 5 (because the dimensions are numbered from 0, as usual). You can also use array_var->Rank to get the number of dimensions for the array.