如何避免帮助函数被警告？(How to avoid helper functions being warned? “ xxx defined but not used”)

如何避免帮助函数被警告？(How to avoid helper functions being warned? “ xxx defined but not used”)

我从这篇文章中学到了在命名空间中创建辅助函数。 'Helper'在C ++中的功能

//stringhelper.hpp namespace utility{ static std::string intToString(int integer) { std::stringstream sstream; sstream << integer; return sstream.str(); } static void toLowerCase(std::string& y) { std::transform(y.begin(), y.end(), y.begin(), (int(*)(int))tolower); } }

我包含此标题但我收到以下警告

'void utility::toLowerCase(std::string&)' defined but not used

是。 我使用intToString（int integer）但不使用toLowerCase（std :: string＆）。 我不希望看到那些警告或每个标题分配一个辅助函数。

有谁能建议一个好的解决方案？ 我应该禁用警告吗？ 谢谢

I learnt from this post here to create helper functions in namespace. 'Helper' functions in C++

//stringhelper.hpp namespace utility{ static std::string intToString(int integer) { std::stringstream sstream; sstream << integer; return sstream.str(); } static void toLowerCase(std::string& y) { std::transform(y.begin(), y.end(), y.begin(), (int(*)(int))tolower); } }

I include this header but I got the following warning

'void utility::toLowerCase(std::string&)' defined but not used

Yes. I used intToString(int integer) but not toLowerCase(std::string&). I don't want to see those warning or divide one helper function per header.

Can anyone suggest a good solution? Should I just disable warning? Thank you

最满意答案

您可以选择关闭该警告：

-Wno-unused-function

在逐个函数的基础上，使用GCC，您可以定义：

void whatever () __attribute__ ((unused)); void whatever () { stuff; }

这告诉GCC该函数可能未被使用。

有关属性的更多信息，请参阅编译器文档

You have the option to turn off that warning:

-Wno-unused-function

On a function-by-function basis, with GCC, you may define:

void whatever () __attribute__ ((unused)); void whatever () { stuff; }

This tells GCC that the function is meant to possibly be unused.

See compiler docs for more info on attribute