python中的递归正则表达式？(Recursive regexp in python?)

python中的递归正则表达式？(Recursive regexp in python?)

我有字符串：

acd (e(fg)h) ij)

我需要在打开和相应的闭括号内删除文本。 所以在示例中我需要删除

(e(fg)h)

结果我想拥有

acd del ij)

我尝试使用下一个代码：

re.sub(r'\((((?>[^()]+)|(?R))*)\)', r'del', 'acd (e(fg)h) ij)')

但是python说：

sre_constants.error: unexpected end of pattern

I have string:

acd (e(fg)h) ij)

I need to delete text within opened and coresponding closed bracket. So in example I need to delete

(e(fg)h)

In result I want to have

acd del ij)

I try to use next code:

re.sub(r'\((((?>[^()]+)|(?R))*)\)', r'del', 'acd (e(fg)h) ij)')

But python say:

sre_constants.error: unexpected end of pattern

最满意答案

谢谢Jerry和devnull！ 用于python的regex模块而不是默认的re模块解决了我的问题

import regex >>> regex.sub(r'\((((?>[^()]+)|(?R))*)\)', r'del', 'acd (e(fg)h) ij)') 'acd del ij)'

Thanks Jerry and devnull! regex module for python instead of default re module solved my issue

import regex >>> regex.sub(r'\((((?>[^()]+)|(?R))*)\)', r'del', 'acd (e(fg)h) ij)') 'acd del ij)'