如何使用log4cxx保留单个文件并覆盖同一文件中的内容?(How to keep single file and overwrite the contents in the same file using log4cxx?)
在我的应用程序中,多个线程将数据记录在同一个文件中。如果文件大小超过限制,那么我必须删除文件中的特定记录并向上移动每个内容。
我可以在Log4cxx中执行此操作吗?如果是,请回复您的想法..
谢谢..
In my application , Multiple threads log the data in the same file .if the file size exceeds the limit , then i have to delete the particular record in file and move every contents upwards.
can I do this in Log4cxx?if so ,reply your thoughts..
Thanks..
最满意答案
此示例将解决您的问题:
log4j.rootLogger=debug, stdout, R log4j.appender.stdout=org.apache.log4j.ConsoleAppender log4j.appender.stdout.layout=org.apache.log4j.PatternLayout # Pattern to output the caller's file name and line number. log4j.appender.stdout.layout.ConversionPattern=%5p [%t] (%F:%L) - %m%n log4j.appender.R=org.apache.log4j.RollingFileAppender log4j.appender.R.File=example.log log4j.appender.R.MaxFileSize=100KB # Keep one backup file log4j.appender.R.MaxBackupIndex = 0 log4j.appender.R.layout=org.apache.log4j.PatternLayout log4j.appender.R.layout.ConversionPattern=%p %t %c - %m%n这将覆盖同一文件中的文件内容。
This sample will solve your problem :
log4j.rootLogger=debug, stdout, R log4j.appender.stdout=org.apache.log4j.ConsoleAppender log4j.appender.stdout.layout=org.apache.log4j.PatternLayout # Pattern to output the caller's file name and line number. log4j.appender.stdout.layout.ConversionPattern=%5p [%t] (%F:%L) - %m%n log4j.appender.R=org.apache.log4j.RollingFileAppender log4j.appender.R.File=example.log log4j.appender.R.MaxFileSize=100KB # Keep one backup file log4j.appender.R.MaxBackupIndex = 0 log4j.appender.R.layout=org.apache.log4j.PatternLayout log4j.appender.R.layout.ConversionPattern=%p %t %c - %m%nThis will override the file contents in the same file.
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