每隔['

每隔['-1']拆分嵌套列表(Splitting Nested List at every ['-1'])

如果我有这样的嵌套列表：

[['01'], ['02'], ['-1'], ['03'], ['04']]

有没有办法在每个['-1']分割这个嵌套列表？

所以它看起来像这样：

[[['01'], ['02']], [['03'], ['04']]]

任何形式的帮助将不胜感激:)

If I have a nested list like this:

[['01'], ['02'], ['-1'], ['03'], ['04']]

Is there a way I split this nested list at every ['-1']?

So that it looks like this:

[[['01'], ['02']], [['03'], ['04']]]

Any sort of help would be appreciated :)

最满意答案

尝试这个，

lists = [['01'], ['02'], ['-1'], ['03'], ['04'], ['-1'], ['05'], ['-1']] results = list() prev_idx = 0 for idx, l in enumerate(lists): if l == ['-1']: results.append(lists[prev_idx:idx]) prev_idx = idx+1 if prev_idx <= idx: # the last group might be [] as shown in this case results.append(lists[prev_idx:]) print(results) # Output [[['01'], ['02']], [['03'], ['04']], [['05']]]

Try this,

lists = [['01'], ['02'], ['-1'], ['03'], ['04'], ['-1'], ['05'], ['-1']] results = list() prev_idx = 0 for idx, l in enumerate(lists): if l == ['-1']: results.append(lists[prev_idx:idx]) prev_idx = idx+1 if prev_idx <= idx: # the last group might be [] as shown in this case results.append(lists[prev_idx:]) print(results) # Output [[['01'], ['02']], [['03'], ['04']], [['05']]]