使用object []和object [] []作为参数的C＃调用方法（params object [] []）(C# call method (params object[][]) with obj

使用object []和object [] []作为参数的C＃调用方法（params object [] []）(C# call method (params object[][]) with object[] and object[][] as parameters)

我有一个方法

public void method(params object[][] arg)

但是在我调用方法的地方，我有对象[]和对象[] []：

object[] var1 = new object[5]; object[][] var2 = new object[8][5]; method(var1, var2); (I´d like this to be method(var1, var2[0], var2[1], var2[2],...)

但是在内部方法中，arg的长度为2：

arg[0] = var1 arg[1] = var2

但我希望arg作为长度为9的数组：

arg[0] = var1 arg[1] = var2[0]; arg[2] = var2[1]; ...

我怎么称呼这个方法？

I have a method

public void method(params object[][] arg)

But where I call the method, I have and object[] and object[][]:

object[] var1 = new object[5]; object[][] var2 = new object[8][5]; method(var1, var2); (I´d like this to be method(var1, var2[0], var2[1], var2[2],...)

But inside method, arg has length 2:

arg[0] = var1 arg[1] = var2

But I want arg as an array of length 9:

arg[0] = var1 arg[1] = var2[0]; arg[2] = var2[1]; ...

How can I call the method?

最满意答案

这听起来像你想要的：

object[][] args = new[] { var1 }.Concat(var2).ToArray(); method(args);

C＃的“普通”参数数组处理不会进行任何展平：您可以使用单个参数调用它，该参数已经是正确的类型， 或者使用元素类型的参数序列调用它。 你不能混搭。

It sounds like you want:

object[][] args = new[] { var1 }.Concat(var2).ToArray(); method(args);

The "normal" parameter array handling of C# doesn't do any flattening: you either call it with a single argument which is already the right type, or you call it with a sequence of arguments of the element type. You can't mix and match.