问题描述
限时送ChatGPT账号..如果我想声明一个包含所有 1 的 128 位向量,这些方法中哪一种总是正确的?
If I want to declare a 128 bit vector of all ones, which one of these methods is always correct?
wire [127:0] mywire;
assign mywire = 128'b1;
assign mywire = {128{1'b1}};
assign mywire = 128'hFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF;
推荐答案
正如快速模拟所证明的那样,assign mywire = 128'b1;
不会分配 mywire
的所有位code> 到 1.只有位 0 被赋值为 1.
As a quick simulation would prove, assign mywire = 128'b1;
does not assign all bits of mywire
to 1. Only bit 0 is assigned 1.
以下两种情况总是将所有 128 位都分配为 1:
Both of the following always assign all 128 bits to 1:
assign mywire = {128{1'b1}};
assign mywire = 128'hFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF;
第一行的一个优点是它更容易扩展到大于和小于 128 的宽度.
One advantage of the 1st line is that it is more easily scalable to widths greater than and less than 128.
对于 SystemVerilog,以下语法也总是将所有 128 位都赋值为 1:
With SystemVerilog, the following syntax also always assigns all 128 bits to 1:
assign mywire = '1;
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