检查列表中是否存在值为x的namedtuple(Check if namedtuple with value x exists in list)

检查列表中是否存在值为x的namedtuple(Check if namedtuple with value x exists in list)

我想查看列表中是否存在namedtuple，类似于：

numbers = [1, 2, 3, 4, 5] if 1 in numbers: do_stuff()

是否有pythonic（或非）方式这样做？ 就像是：

namedtuples = [namedtuple_1, namedtuple_2, namedtuple3] if (namedtuple with value x = 1) in namedtuples: do stuff()

I want to see if a namedtuple exists in a list, similar to:

numbers = [1, 2, 3, 4, 5] if 1 in numbers: do_stuff()

is there a pythonic (or not) way to do this? Something like:

namedtuples = [namedtuple_1, namedtuple_2, namedtuple3] if (namedtuple with value x = 1) in namedtuples: do stuff()

最满意答案

使用any ：

演示：

>>> from collections import namedtuple >>> A = namedtuple('A', 'x y') >>> lis = [A(100, 200), A(10, 20), A(1, 2)] >>> any(a.x==1 for a in lis) True >>> [getattr(a, 'x')==1 for a in lis] [False, False, True]

Use any:

Demo:

>>> from collections import namedtuple >>> A = namedtuple('A', 'x y') >>> lis = [A(100, 200), A(10, 20), A(1, 2)] >>> any(a.x==1 for a in lis) True >>> [getattr(a, 'x')==1 for a in lis] [False, False, True]