如何强制signal.sawtooth从0开始？(How to force the signal.sawtooth to start by 0?)

如何强制signal.sawtooth从0开始？(How to force the signal.sawtooth to start by 0?)

这可能是一个简单的伎俩，但我不会马上得到它。 我希望锯齿信号从（0,0）开始并上升一个周期的1/4，这样就像窦一样，而不是从（0，-1）开始。

from scipy import signal import matplotlib.pyplot as plt t = np.linspace(0, 1, 500) plt.plot(t, signal.sawtooth(2 * np.pi * 5 * t))

it might be a simple trick, but I don't get it right away. I would like the sawtooth signal to start by (0,0) and go up for a 1/4th of a period so like a sinus would do instead of starting by (0,-1).

from scipy import signal import matplotlib.pyplot as plt t = np.linspace(0, 1, 500) plt.plot(t, signal.sawtooth(2 * np.pi * 5 * t))

最满意答案

通过pi延迟相位

from scipy import signal import matplotlib.pyplot as plt t = np.linspace(0, 1, 500) plt.plot(t, signal.sawtooth(2 * np.pi * 5 * t-np.pi)) plt.show()

只需在参数中添加-np.pi term即可

Delay the phase by pi

from scipy import signal import matplotlib.pyplot as plt t = np.linspace(0, 1, 500) plt.plot(t, signal.sawtooth(2 * np.pi * 5 * t-np.pi)) plt.show()

Just add -np.pi term in the argument