Tcl：如何通过键列表从嵌套字典中获取值(Tcl: How to get value from nested dictionary by list of keys)

Tcl：如何通过键列表从嵌套字典中获取值(Tcl: How to get value from nested dictionary by list of keys)

我很难通过使用键列表访问嵌套字典中的值。

dict set testDict library [dict create NY [dict create section [dict create adult [dict create book cinderella]]]] library {NY {section {adult {book cinderella}}}} # I can access the value by: dict get $testDict library NY section adult book cinderella # cannot access the same by list of keys in a variable set keyLst {library NY section adult book} library NY section adult book set keyStr "library NY section adult book" library NY section adult book dict get $testDict $keyLst key "library NY section adult book" not known in dictionary dict get $testDict $keyStr key "library NY section adults book" not known in dictionary # The only not elegant solution I came up is using eval + list eval dict get \$testDict $keyStr key "adults" not known in dictionary eval dict get \$testDict $keyLst cinderella

虽然eval在这种情况下起作用 - 必须有更好的方法直接执行此操作。

知道如何通过变量中的键列表访问嵌套字典值吗？

I have difficulty accessing values in nested dictionary by using list of keys.

dict set testDict library [dict create NY [dict create section [dict create adult [dict create book cinderella]]]] library {NY {section {adult {book cinderella}}}} # I can access the value by: dict get $testDict library NY section adult book cinderella # cannot access the same by list of keys in a variable set keyLst {library NY section adult book} library NY section adult book set keyStr "library NY section adult book" library NY section adult book dict get $testDict $keyLst key "library NY section adult book" not known in dictionary dict get $testDict $keyStr key "library NY section adults book" not known in dictionary # The only not elegant solution I came up is using eval + list eval dict get \$testDict $keyStr key "adults" not known in dictionary eval dict get \$testDict $keyLst cinderella

While eval works in this instance - There must be better way to do this directly.

Any idea how to access nested dictionary values by key list in variable?

最满意答案

您需要将列表（或字符串）扩展为单独的单词。 dict不会将list作为参数。

dict get $testDict {*}$keyLst

参考文献： dict ; 论证扩展

You need to expand the list (or string) into separate words. dict does not take a list as an argument.

dict get $testDict {*}$keyLst

References: dict ; argument expansion