从两个数组中仅删除一个匹配元素(Remove only one matching element from two arrays)

从两个数组中仅删除一个匹配元素(Remove only one matching element from two arrays) $array1 = array(1.99); $array2 = array(1.99, 1.99, 2.99);

我想从$ array2中只删除$ array1的一个匹配元素。

所以，我想要的是：

1.99 2.99

我已经尝试了array_diff() ，它将取出1.99并且只留下2.99 。

$array1 = array(1.99); $array2 = array(1.99, 1.99, 2.99);

I want to remove only one matching element of $array1, from $array2.

so, What I want is:

1.99 2.99

Ive tried array_diff(), which will take out both of the 1.99 and leave me with only 2.99.

最满意答案

你可以利用这个事实， array_search只返回目标数组中的一个匹配元素，并使用它从$array2删除它：

$array1 = array(1.99); $array2 = array(1.99, 1.99, 2.99); foreach ($array1 as $remove) { unset($array2[array_search($remove, $array2)]); }

如果$array1可以包含$array2中不存在的元素，那么您需要添加一个检查，结果array_search不是false。

You can take advantage of the fact array_search will only return one matching element from the target array, and use it to remove that from $array2:

$array1 = array(1.99); $array2 = array(1.99, 1.99, 2.99); foreach ($array1 as $remove) { unset($array2[array_search($remove, $array2)]); }

If $array1 can contain elements that aren't present in $array2 then you'll need to add a check that the result of array_search is not false.