使用 Tkinter 实现密码对话框

本文介绍了使用 Tkinter 实现密码对话框的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

限时送ChatGPT账号..

我正在尝试实现一个获取用户密码的对话框.我创建了从 tk.Toplevel 继承的 PasswordDiaglog 类，但这会导致它的执行不阻塞父框架的问题.

I am attempting to implement a dialog that gets the users password. I have created the class PasswordDiaglog that inherits from tk.Toplevel but this causes the problem that it's execution is non-blocking of the parent frame.

import Tkinter as tk

class PasswordDialog(tk.Toplevel):
    def __init__(self, parent):
        tk.Toplevel.__init__(self)
        self.password = None
        self.entry = tk.Entry(self, show='*')
        self.entry.pack()
        self.button = tk.Button(self)
        self.button["text"] = "Submit"
        self.button["command"] = self.StorePass
        self.button.pack()

    def StorePass(self):
        self.password = self.entry.get()
        self.destroy()
        print '1: Password was', self.password

class MainApplication(tk.Frame):
    def __init__(self, root):
        tk.Frame.__init__(self, root)
        self.button = tk.Button(self)
        self.button["text"] = "Password"
        self.button["command"] = self.GetPassword
        self.button.pack()

    def GetPassword(self):
        passwd = PasswordDialog(self)
        # HALT HERE 
        print '2: Password was', passwd.password

if __name__ == "__main__":
    root = tk.Tk()
    MainApplication(root).pack(side="top", fill="both", expand=True)
    root.mainloop()

通过运行我的代码，将提交的 foobar 作为密码，在终端中可以看到以下输出:

By running my code a submitting foobar as the password the following output is seen in the terminal:

2: Password was None
1: Password was foobar

预期的输出应该是:

1: Password was foobar
2: Password was foobar

关于如何解决这个问题或如何实现密码对话框的任何想法?

Any ideas on how to solve this or how to implement a password dialog in general?

在输入 entry 后按回车键也可以调用 StoredPass().

It would also be nice to call StoredPass() by hitting return after typing in the entry.

推荐答案

将密码存储为 MainAplication 类的属性，并使用传入的 parent 作为句柄PasswordDialog 类意味着你可以使用 self.wait_window(PasswordDialog(self)) 来阻止执行，直到 PasswordDialog 被销毁:

Storing the password as attribute of the MainAplication class and using the passed in parent as the handle from the PasswordDialog class means you can use self.wait_window(PasswordDialog(self)) to block the execution until the PasswordDialog is destroyed:

import Tkinter as tk

class PasswordDialog(tk.Toplevel):
    def __init__(self, parent):
        tk.Toplevel.__init__(self)
        self.parent = parent
        self.entry = tk.Entry(self, show='*')
        self.entry.bind("<KeyRelease-Return>", self.StorePassEvent)
        self.entry.pack()
        self.button = tk.Button(self)
        self.button["text"] = "Submit"
        self.button["command"] = self.StorePass
        self.button.pack()

    def StorePassEvent(self, event):
        self.StorePass()

    def StorePass(self):
        self.parent.password = self.entry.get()
        self.destroy()
        print '1: Password was', self.parent.password

class MainApplication(tk.Frame):
    def __init__(self, root):
        tk.Frame.__init__(self, root)
        self.password = None
        self.button = tk.Button(self)
        self.button["text"] = "Password"
        self.button["command"] = self.GetPassword
        self.button.pack()

    def GetPassword(self):
        self.wait_window(PasswordDialog(self))
        print '2: Password was', self.password

if __name__ == "__main__":
    root = tk.Tk()
    MainApplication(root).pack(side="top", fill="both", expand=True)
    root.mainloop()

现在输出符合预期:

1: Password was foobar
2: Password was foobar

<小时>

要绑定回车键，您可以使用:

---

To bind the Return key you can use:

self.entry.bind("<KeyRelease-Return>", self.StorePassEvent)

带有包装函数:

def StorePassEvent(self, event):
    self.StorePass()

您也可以使用 lambda 代替:

You can also use lambda instead:

self.entry.bind("<KeyRelease-Return>", lambda x: self.StorePass())

这篇关于使用 Tkinter 实现密码对话框的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！