通过 Tkinter 中的按钮关闭窗口并打开一个新窗口

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问题描述

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我想知道是否有办法打开 Toplevel() 的新实例并通过按下按钮关闭当前实例，即关闭当前窗口并打开一个新窗口.这是有问题的代码:

def start(self):self.name = tk.DoubleVar()name_w = tk.Toplevel(root)name_w.wm_title("输入姓名")f1 = tk.Frame(name_w)f1.pack()L1 = tk.Label(f1, text="请输入您的姓名！")L1.grid(行=0，列=0)E1 = tk.Entry(f1, textvariable=self.name)E1.grid(行=1，列=0)N1 = tk.Button(f1, text="Next", command = self.Q1)N1.grid(行=2，列=0)

在这种情况下，我希望调用 self.Q1，同时销毁 name_w.有没有办法做到这一点?谢谢.

解决方案

是的，这是可能的.要关闭 Toplevel 的实例，只需将其销毁即可.您需要保存对窗口的引用.在你的情况下，我要么让 Q1 销毁窗口，要么创建一个单独的函数来调用 Q1 然后销毁窗口.这完全取决于Q1的主要目的是什么.

例如:

def start(self):...self.new_window = name_w...def quit_window(self):self.Q1()self.new_window.destroy()

如果您有多个这些，您可能需要将窗口引用存储在列表或字典中，但基本机制是相同的:使用 .destroy() 销毁窗口.>

当然，这不是唯一的方法.您可以使用 lambda 或 functools.partial 以及一个接受要销毁的窗口名称的函数，或者您可以使用嵌套函数等.

I was wondering if there was a way to open a new instance of Toplevel() and close the current one via the press of a button, i.e. close the current window and open a new one. Here is the code in question:

def start(self):
        self.name = tk.DoubleVar()
        name_w = tk.Toplevel(root)
        name_w.wm_title("Enter name")
        f1 = tk.Frame(name_w)
        f1.pack()
        L1 = tk.Label(f1, text="Please enter your name!")
        L1.grid(row=0, column=0)
        E1 = tk.Entry(f1, textvariable=self.name)
        E1.grid(row=1, column=0)
        N1 = tk.Button(f1, text="Next", command = self.Q1)
        N1.grid(row=2, column=0)

In this case, I want self.Q1 to be called, while also destroying name_w. Is there anyway to do this? Thanks.

解决方案

Yes, it's possible. To close an instance of Toplevel simply destroy it. You'll need to save a reference to the window. In your case I would either have Q1 destroy the window, or make a separate function that calls Q1 and then destroys the window. It all depends on what the main purpose of Q1 is.

For example:

def start(self):
    ...
    self.new_window = name_w
    ...

def quit_window(self):
    self.Q1()
    self.new_window.destroy()

If you have multiple of these you might need to store the window references in a list or dictionary, but the basic mechanism is the same: use .destroy() to destroy the window.

This isn't the only way, of course. You could use lambda or functools.partial and a function that accepts the name of the window to destroy, or you could use nested functions, etc.

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