问题描述
限时送ChatGPT账号..我在输入 Tkinter 条目时遇到问题.我做了一个注册码,我的代码上的每个条目都调用了一个虚拟键盘,虚拟键盘是分开的python程序.我成功调用了另一个 python 程序,但我无法使用我调用的虚拟键盘在我的 Tkinter 条目上输入,这是我的主程序.有什么办法可以做到这一点吗?这是我的代码
def register(self):self.master_register = Toplevel()self.first_name = StringVar()self.middle_name = StringVar()self.last_name = StringVar()self.sex = StringVar()self.birth_day = StringVar()self.civil_status = StringVar()self.label_head = Label(self.master_register, text = "请填写以下所有信息")self.label_head.pack()self.label_first_name = Label(self.master_register, text = "First Name")self.label_first_name.pack()self.entry_first_name = Entry(self.master_register, textvariable = self.first_name)self.entry_first_name.pack()self.entry_first_name.bind('',self.keyboard)self.label_middle_name = Label(self.master_register, text = "Middle Name")self.label_middle_name.pack()self.entry_middle_name = Entry(self.master_register, textvariable = self.middle_name)self.entry_middle_name.pack()self.entry_middle_name.bind('',self.keyboard)self.label_last_name = Label(self.master_register, text = "Last Name")self.label_last_name.pack()self.entry_last_name = Entry(self.master_register, textvariable = self.last_name)self.entry_last_name.pack()self.entry_last_name.bind('',self.keyboard)self.label_sex = Label(self.master_register, text = "Sex")self.label_sex.pack()self.radio_button_sex1 = Radiobutton(self.master_register, text = "Male", variable = self.sex, value = "Male" )self.radio_button_sex1.pack()self.radio_button_sex2 = Radiobutton(self.master_register, text = "Female", variable = self.sex, value = "Female")self.radio_button_sex2.pack()self.label_birthday = Label(self.master_register, text = "生日")self.label_birthday.pack()self.entry_birthday = Entry(self.master_register, textvariable = self.birth_day)self.entry_birthday.pack()self.entry_birthday.bind('',self.keyboard)self.label_civil_status = Label(self.master_register, text = "Civil Status")self.label_civil_status.pack()self.entry_civil_status = Entry(self.master_register, textvariable = self.civil_status)self.entry_civil_status.pack()self.entry_civil_status.bind('',self.keyboard)self.button_submit = Button(self.master_register, text = "Submit", command = lambda: self.registered(self.first_name, self.middle_name,self.last_name, self.sex, self.birth_day,self.civil_status))self.button_submit.pack()定义键盘(自我,事件):exec(open("keyboardclass.py").read());
这是我的键盘类.py
def select(value):如果值==空格":entry1.insert(tkinter.END, ' ')elif 值 ==退格":entry1.delete(len(entry1.get())-1,tkinter.END)别的:entry1.insert(tkinter.END,值)根 = Tk()root.configure(background = "cornflowerblue")root.wm_attributes("-alpha", 0.7)字母 = ['`','1','2','3','4','5','6','7','8','9','0','-','=','<-退格','Tab','q','w','e','r','t','y','u','i','o','p','[',']',"\\",'Caps Lock','a','s','d','f','g','h','j','k','l',';',"'",'进入','Shift','z','x','c','v','b','n','m',',','.','/','Shift','空间']行 = 2列 = 0对于字母表中的字母表:命令 = lambda x=字母:选择(x)如果字母 != '空格':按钮(根,文本 = 字母,command = command,width = 5, padx=3, pady=3,bd=12,bg = "black", fg="white").grid(row = Row, column = Column)如果字母 == '回车':按钮(根,文本 = 字母,command = command, width = 15, padx=3, pady=3,bd=12,bg = "black", fg="white").grid(row = Row, column = Column, columnspan = 2)如果字母 == 'Shift':按钮(根,文本 = 字母,command = command, width = 15, padx=3, pady=3,bd=12,bg = "black", fg="white").grid(row = Row, column = Column, columnspan = 2)如果字母 == '空格':按钮(根,文本 = 字母,command = command, width = 130, padx=3, pady=3,bd=12,bg = "black", fg="white").grid(row = 6, columnspan = 16)列 +=1如果列>13 和行 == 1:列 = 0行 += 1如果列>13 和行 == 2:列 = 0行 +=1如果列>13 和行 == 3:列 = 0行 +=1如果列>12 和行 == 4:列 = 0行 +=1
root.mainloop()
解决方案keyboard.py
我将代码放在函数 create()
中,它获取 root
和 entry
作为参数 - 所以现在我可以使用 import 键盘
其他文件并运行 keyboard.create(root, some_entry)
.
它使用 root
创建窗口 Toplevel()
而不是 Tk()
- 并且没有第二个 mainloop()
代码>.
它使用 entry
在 select(entry, value)
中使用它,这将使用 entry.insert(...)
>
if __name__ == "__main__"
中有代码:因此您可以将其作为独立程序运行以测试键盘.
它显示两个Entry
和一个Text
(您可以在其中测试键Enter
).
我为Enter
、Tab
、Backspace
添加了Text
的代码(这需要不同的方法).当您按 Shift
或 Caps Lock
时,它会开始插入大写字符 - 但它不会更改窗口中按钮上的文本.
在 alphabets
中我将行分组到列表中,所以我不需要 if/else
来检查字符是否应该在下一行 - 我可以使用两个 for
-循环.
导入 tkinter 作为 tk字母 = [['`','1','2','3','4','5','6','7','8','9','0','-','=','退格'],['Tab','q','w','e','r','t','y','u','i','o','p','[',']',"\\"],['Caps Lock','a','s','d','f','g','h','j','k','l',';',"'",'进入'],['Shift','z','x','c','v','b','n','m',',','.','/','Shift'],['空间']]uppercase = False # 使用大写字符.定义选择(条目,值):全局大写如果值==空格":值 = ' 'elif 值 == '回车':值 = '\n'elif 值 == 'Tab':值 = '\t'如果值==退格":如果 isinstance(entry, tk.Entry):entry.delete(len(entry.get())-1, 'end')#elif isinstance(entry, tk.Text):其他:# tk.Textentry.delete('end - 2c', 'end')('Caps Lock', 'Shift') 中的 elif 值:uppercase = not uppercase # 将 True 改为 False,或 False 为 True别的:如果大写:值 = value.upper()entry.insert('end', value)定义创建(根,条目):窗口 = tk.Toplevel(root)window.configure(background="cornflowerblue")window.wm_attributes("-alpha", 0.7)对于 y, enumerate(alphabets) 中的行:x = 0#for x, enumerate(row) 中的文本:对于行中的文本:如果文本在 ('Enter', 'Shift'):宽度 = 15列跨度 = 2elif 文本 == '空格':宽度 = 130列跨度 = 16别的:宽度 = 5列跨度 = 1tk.Button(window, text=text, width=width,命令=拉姆达值=文本:选择(条目,值),padx=3, pady=3, bd=12, bg="black", fg="white").grid(row=y, column=x, columnspan=columnspan)x += 列跨度# - - 主要的 - -如果 __name__ == '__main__':根 = tk.Tk()root.title('测试键盘')label = tk.Label(root, text='测试键盘')label.grid(row=0, column=0, columnspan=2)entry1 = tk.Entry(root)entry1.grid(row=1, column=0,sticky='news')button1 = tk.Button(root, text='Keyboard', command=lambda:create(root, entry1))button1.grid(row=1, column=1,sticky='news')entry2 = tk.Entry(root)entry2.grid(row=2, column=0,sticky='news')button2 = tk.Button(root, text='Keyboard', command=lambda:create(root, entry2))button2.grid(row=2, column=1,sticky='news')text1 = tk.Text(root)text1.grid(row=3, column=0,sticky='news')button3 = tk.Button(root, text='Keyboard', command=lambda:create(root, text1))button3.grid(row=3, column=1,sticky='news')root.mainloop()
<小时>
main.py
它导入 keyboard
并使用 keyboard.create(...)
来显示键盘并将其分配给选定的 Entry
或 文字
.
导入 tkinter 作为 tk进口键盘# - - 主要的 - -如果 __name__ == '__main__':根 = tk.Tk()root.title('你好世界!')label = tk.Label(root, text='Form')label.grid(row=0, column=0, columnspan=3)#-----label1 = tk.Label(root, text='Entry 1')label1.grid(row=1, column=0)entry1 = tk.Entry(root)entry1.grid(row=1, column=1,sticky='news')button1 = tk.Button(root, text='Keyboard', command=lambda:keyboard.create(root, entry1))button1.grid(row=1, column=2,sticky='news')#-----label2 = tk.Label(root, text='Entry 2')label2.grid(row=2, column=0)entry2 = tk.Entry(root)entry2.grid(row=2, column=1,sticky='news')button2 = tk.Button(root, text='Keyboard', command=lambda:keyboard.create(root, entry2))button2.grid(row=2, column=2,sticky='news')#-----label3 = tk.Label(root, text='Text 1')label3.grid(row=3, column=0)text1 = tk.Text(root)text1.grid(row=3, column=1,sticky='news')button3 = tk.Button(root, text='Keyboard', command=lambda:keyboard.create(root, text1))button3.grid(row=3, column=2,sticky='news')root.mainloop()
<小时>
我正在考虑创建具有 Entry + Button Keyboard
的小部件,因为您经常使用这种组合.也许我稍后会创建它.
I'm having a problem with typing into my Tkinter entry. I did a registration code and with every entry on my code calls a virtual keyboard, the virtual keyboard is separated python program. I successfully called another python program but I can't type on my Tkinter entry which is my main program using the virtual keyboard I called. Is there any way to get this done? here is my code
def register(self):
self.master_register = Toplevel()
self.first_name = StringVar()
self.middle_name = StringVar()
self.last_name = StringVar()
self.sex = StringVar()
self.birth_day = StringVar()
self.civil_status = StringVar()
self.label_head = Label(self.master_register, text = "Please fill up all informations below")
self.label_head.pack()
self.label_first_name = Label(self.master_register, text = "First Name")
self.label_first_name.pack()
self.entry_first_name = Entry(self.master_register, textvariable = self.first_name)
self.entry_first_name.pack()
self.entry_first_name.bind('<ButtonPress-1>',self.keyboard)
self.label_middle_name = Label(self.master_register, text = "Middle Name")
self.label_middle_name.pack()
self.entry_middle_name = Entry(self.master_register, textvariable = self.middle_name)
self.entry_middle_name.pack()
self.entry_middle_name.bind('<ButtonPress-1>',self.keyboard)
self.label_last_name = Label(self.master_register, text = "Last Name")
self.label_last_name.pack()
self.entry_last_name = Entry(self.master_register, textvariable = self.last_name)
self.entry_last_name.pack()
self.entry_last_name.bind('<ButtonPress-1>',self.keyboard)
self.label_sex = Label(self.master_register, text = "Sex")
self.label_sex.pack()
self.radio_button_sex1 = Radiobutton(self.master_register, text = "Male", variable = self.sex, value = "Male" )
self.radio_button_sex1.pack()
self.radio_button_sex2 = Radiobutton(self.master_register, text = "Female", variable = self.sex, value = "Female")
self.radio_button_sex2.pack()
self.label_birthday = Label(self.master_register, text = "Birth Day")
self.label_birthday.pack()
self.entry_birthday = Entry(self.master_register, textvariable = self.birth_day)
self.entry_birthday.pack()
self.entry_birthday.bind('<ButtonPress-1>',self.keyboard)
self.label_civil_status = Label(self.master_register, text = "Civil Status")
self.label_civil_status.pack()
self.entry_civil_status = Entry(self.master_register, textvariable = self.civil_status)
self.entry_civil_status.pack()
self.entry_civil_status.bind('<ButtonPress-1>',self.keyboard)
self.button_submit = Button(self.master_register, text = "Submit", command = lambda: self.registered(self.first_name, self.middle_name,
self.last_name, self.sex, self.birth_day,
self.civil_status))
self.button_submit.pack()
def keyboard(self, event):
exec(open("keyboardclass.py").read());
here is my keyboardclass.py
def select(value):
if value == "Space":
entry1.insert(tkinter.END, ' ')
elif value == "Backspace":
entry1.delete(len(entry1.get())-1,tkinter.END)
else:
entry1.insert(tkinter.END, value)
root = Tk()
root.configure(background = "cornflowerblue")
root.wm_attributes("-alpha", 0.7)
alphabets = ['`','1','2','3','4','5','6','7','8','9','0','-','=','<-
Backspace',
'Tab','q','w','e','r','t','y','u','i','o','p','[',']',"\\",
'Caps Lock','a','s','d','f','g','h','j','k','l',';',"'",'Enter',
'Shift','z','x','c','v','b','n','m',',','.','/','Shift',
'Space']
Row = 2
Column = 0
for alphabet in alphabets:
command = lambda x=alphabet: select(x)
if alphabet != 'Space':
Button(root, text = alphabet,
command = command,width = 5, padx=3, pady=3,bd=12,bg = "black", fg="white").grid(row = Row, column = Column)
if alphabet == 'Enter':
Button(root, text = alphabet,
command = command, width = 15, padx=3, pady=3,bd=12,bg = "black", fg="white").grid(row = Row, column = Column, columnspan = 2)
if alphabet == 'Shift':
Button(root, text = alphabet,
command = command, width = 15, padx=3, pady=3,bd=12,bg = "black", fg="white").grid(row = Row, column = Column, columnspan = 2)
if alphabet == 'Space':
Button(root, text = alphabet,
command = command, width = 130, padx=3, pady=3,bd=12,bg = "black", fg="white").grid(row = 6, columnspan = 16)
Column +=1
if Column > 13 and Row == 1:
Column = 0
Row += 1
if Column > 13 and Row == 2:
Column = 0
Row +=1
if Column > 13 and Row == 3:
Column = 0
Row +=1
if Column > 12 and Row == 4:
Column = 0
Row +=1
root.mainloop()
解决方案keyboard.py
I put code in function create()
which gets root
and entry
as arguments - so now I can use import keyboard
it other file and run keyboard.create(root, some_entry)
.
It uses root
to create window Toplevel()
instead of Tk()
- and without second mainloop()
.
It uses entry
to use it in select(entry, value)
which will use entry.insert(...)
There is code in if __name__ == "__main__"
: so you can run it as standalone program to test keyboard.
It displays two Entry
and one Text
(in which you can test key Enter
).
I added code for Enter
, Tab
, Backspace
for Text
(which needs different method). When you press Shift
or Caps Lock
then it starts to insert uppercase chars - but it doesn't change text on buttons in window.
In alphabets
I grouped rows in lists so I don't need if/else
to check if char should be in next row - I can use two for
-loops.
import tkinter as tk
alphabets = [
['`','1','2','3','4','5','6','7','8','9','0','-','=','Backspace'],
['Tab','q','w','e','r','t','y','u','i','o','p','[',']',"\\"],
['Caps Lock','a','s','d','f','g','h','j','k','l',';',"'",'Enter'],
['Shift','z','x','c','v','b','n','m',',','.','/','Shift'],
['Space']
]
uppercase = False # use uppercase chars.
def select(entry, value):
global uppercase
if value == "Space":
value = ' '
elif value == 'Enter':
value = '\n'
elif value == 'Tab':
value = '\t'
if value == "Backspace":
if isinstance(entry, tk.Entry):
entry.delete(len(entry.get())-1, 'end')
#elif isinstance(entry, tk.Text):
else: # tk.Text
entry.delete('end - 2c', 'end')
elif value in ('Caps Lock', 'Shift'):
uppercase = not uppercase # change True to False, or False to True
else:
if uppercase:
value = value.upper()
entry.insert('end', value)
def create(root, entry):
window = tk.Toplevel(root)
window.configure(background="cornflowerblue")
window.wm_attributes("-alpha", 0.7)
for y, row in enumerate(alphabets):
x = 0
#for x, text in enumerate(row):
for text in row:
if text in ('Enter', 'Shift'):
width = 15
columnspan = 2
elif text == 'Space':
width = 130
columnspan = 16
else:
width = 5
columnspan = 1
tk.Button(window, text=text, width=width,
command=lambda value=text: select(entry, value),
padx=3, pady=3, bd=12, bg="black", fg="white"
).grid(row=y, column=x, columnspan=columnspan)
x += columnspan
# --- main ---
if __name__ == '__main__':
root = tk.Tk()
root.title('Test Keyboard')
label = tk.Label(root, text='Test Keyboard')
label.grid(row=0, column=0, columnspan=2)
entry1 = tk.Entry(root)
entry1.grid(row=1, column=0, sticky='news')
button1 = tk.Button(root, text='Keyboard', command=lambda:create(root, entry1))
button1.grid(row=1, column=1, sticky='news')
entry2 = tk.Entry(root)
entry2.grid(row=2, column=0, sticky='news')
button2 = tk.Button(root, text='Keyboard', command=lambda:create(root, entry2))
button2.grid(row=2, column=1, sticky='news')
text1 = tk.Text(root)
text1.grid(row=3, column=0, sticky='news')
button3 = tk.Button(root, text='Keyboard', command=lambda:create(root, text1))
button3.grid(row=3, column=1, sticky='news')
root.mainloop()
main.py
It imports keyboard
and uses keyboard.create(...)
to show keyboard and assing it to selected Entry
or Text
.
import tkinter as tk
import keyboard
# --- main ---
if __name__ == '__main__':
root = tk.Tk()
root.title('Hello World!')
label = tk.Label(root, text='Form')
label.grid(row=0, column=0, columnspan=3)
#-----
label1 = tk.Label(root, text='Entry 1')
label1.grid(row=1, column=0)
entry1 = tk.Entry(root)
entry1.grid(row=1, column=1, sticky='news')
button1 = tk.Button(root, text='Keyboard', command=lambda:keyboard.create(root, entry1))
button1.grid(row=1, column=2, sticky='news')
#-----
label2 = tk.Label(root, text='Entry 2')
label2.grid(row=2, column=0)
entry2 = tk.Entry(root)
entry2.grid(row=2, column=1, sticky='news')
button2 = tk.Button(root, text='Keyboard', command=lambda:keyboard.create(root, entry2))
button2.grid(row=2, column=2, sticky='news')
#-----
label3 = tk.Label(root, text='Text 1')
label3.grid(row=3, column=0)
text1 = tk.Text(root)
text1.grid(row=3, column=1, sticky='news')
button3 = tk.Button(root, text='Keyboard', command=lambda:keyboard.create(root, text1))
button3.grid(row=3, column=2, sticky='news')
root.mainloop()
I was thinking to create widget which has Entry + Button Keyboard
because you use this combination very often. Maybe I create it later.
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