从列表名称中创建嵌套列表(Create a nested list out of list names)

从列表名称中创建嵌套列表(Create a nested list out of list names) list1 <- 1:3 list2 <- letters[1:3]

我想将它们组合在一个列表中，但不是简单地将它们列在list(list1, list2) ，而是以更通用的方式。

例如，通过使用ls(pattern = "^list*") 。 但是，这只是组合名称而不是实际列表。 您如何访问，替换或引用实际列表？

list1 <- 1:3 list2 <- letters[1:3]

I'd like to combine them in a list but not by simple listing them in list(list1, list2), but in a more generalized fashion.

For example, by using ls(pattern = "^list*"). However, that only combines the names and not the actual lists. How do you access, substitute, or refer to the actual lists?

最满意答案

听起来你正在寻找mget ：

list1 <- 1:3 list2 <- letters[1:3] mget(ls(pattern = "list\\d")) # $list1 # [1] 1 2 3 # # $list2 # [1] "a" "b" "c"

It sounds like you're looking for mget:

list1 <- 1:3 list2 <- letters[1:3] mget(ls(pattern = "list\\d")) # $list1 # [1] 1 2 3 # # $list2 # [1] "a" "b" "c"