为什么命令提示符在我开始之前显示数字？(Why does command prompt show numbers before I begin?)

为什么命令提示符在我开始之前显示数字？(Why does command prompt show numbers before I begin?)

命令提示符在程序开始之前显示数字。 为什么？ 给出了2687688但数字不会写入文件？

#include <stdio.h> #include <conio.h> int main(void){ FILE*nfPtr; int n; if ((nfPtr=fopen("c:\\Users\\raphaeljones\\Desktop\\newfile.dat","w"))==NULL) { printf ("Sorry! The file cannot be opened\n"); } else {//else 1 begin printf("Enter numbers to be stored in file\n"); printf("%d",&n); while (!feof(stdin)){ fprintf(nfPtr,"%d",n); scanf("%d",&n); } }//else 1 ends fclose(nfPtr); getch(); return 0; }

The command prompt shows numbers before program begins. Why? 2687688 is given but the numbers won't write to file?

#include <stdio.h> #include <conio.h> int main(void){ FILE*nfPtr; int n; if ((nfPtr=fopen("c:\\Users\\raphaeljones\\Desktop\\newfile.dat","w"))==NULL) { printf ("Sorry! The file cannot be opened\n"); } else {//else 1 begin printf("Enter numbers to be stored in file\n"); printf("%d",&n); while (!feof(stdin)){ fprintf(nfPtr,"%d",n); scanf("%d",&n); } }//else 1 ends fclose(nfPtr); getch(); return 0; }

最满意答案

替代

printf("%d",&n);

同

scanf("%d",&n);

printf将格式指向的C字符串写入标准输出（stdout）

scanf从stdin读取数据

在您的代码中，您打印n，即未初始化，在"Enter numbers to be stored in file"字符串后打印出一个随机数。

Substitute

printf("%d",&n);

with

scanf("%d",&n);

printf Writes the C string pointed by format to the standard output (stdout)

scanf Reads data from stdin

In your code you are printing n, that is not initialized, that a random number is printed out after "Enter numbers to be stored in file" string.