使用XSL在第一个位置插入XML节点(Insert XML node at first position using XSL)
如果导入不存在,XSLT将当前插入导入
<?xml version="1.0" encoding="utf-8"?> <Project DefaultTargets="Build" ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003"> ... ... <Import Project="$(SolutionDir)BuildShared.targets" /> </Project>我需要它作为第一个节点插入它
<?xml version="1.0" encoding="utf-8"?> <Project DefaultTargets="Build" ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003"> <Import Project="$(SolutionDir)BuildShared.targets" /> ... ... </Project>template.xsl;
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ms="http://schemas.microsoft.com/developer/msbuild/2003"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match='@*|node()'> <xsl:copy> <xsl:apply-templates select='@*|node()'/> </xsl:copy> </xsl:template> <xsl:template match="/ms:Project[not(ms:Import[@Project='$(SolutionDir)BuildConfiguration.targets'])]"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> <Import xmlns="http://schemas.microsoft.com/developer/msbuild/2003" Project="$(SolutionDir)BuildConfiguration.targets"/> </xsl:copy> </xsl:template> </xsl:stylesheet>交换导入和apply-templates行给出;
runtime error: file template.xsl line 9 element copy
Attribute nodes must be added before any child nodes to an element.
The XSLT will currently insert the import if it doesn't exist
<?xml version="1.0" encoding="utf-8"?> <Project DefaultTargets="Build" ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003"> ... ... <Import Project="$(SolutionDir)BuildShared.targets" /> </Project>I need it to insert it as the first node
<?xml version="1.0" encoding="utf-8"?> <Project DefaultTargets="Build" ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003"> <Import Project="$(SolutionDir)BuildShared.targets" /> ... ... </Project>template.xsl;
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ms="http://schemas.microsoft.com/developer/msbuild/2003"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match='@*|node()'> <xsl:copy> <xsl:apply-templates select='@*|node()'/> </xsl:copy> </xsl:template> <xsl:template match="/ms:Project[not(ms:Import[@Project='$(SolutionDir)BuildConfiguration.targets'])]"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> <Import xmlns="http://schemas.microsoft.com/developer/msbuild/2003" Project="$(SolutionDir)BuildConfiguration.targets"/> </xsl:copy> </xsl:template> </xsl:stylesheet>Swapping the import and apply-templates lines gives;
runtime error: file template.xsl line 9 element copy
Attribute nodes must be added before any child nodes to an element.
最满意答案
只需为node()和@*分别执行xsl:apply-templates :
<xsl:template match="/ms:Project[not(ms:Import[@Project='$(SolutionDir)BuildConfiguration.targets'])]"> <xsl:copy> <xsl:apply-templates select="@*"/> <Import xmlns="http://schemas.microsoft.com/developer/msbuild/2003" Project="$(SolutionDir)BuildConfiguration.targets"/> <xsl:apply-templates select="node()"/> </xsl:copy> </xsl:template>Just do your xsl:apply-templates for node() and @* separately:
<xsl:template match="/ms:Project[not(ms:Import[@Project='$(SolutionDir)BuildConfiguration.targets'])]"> <xsl:copy> <xsl:apply-templates select="@*"/> <Import xmlns="http://schemas.microsoft.com/developer/msbuild/2003" Project="$(SolutionDir)BuildConfiguration.targets"/> <xsl:apply-templates select="node()"/> </xsl:copy> </xsl:template>更多推荐
xsl,<xsl,template,电脑培训,计算机培训,IT培训"/> <meta name="descript
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