如何获取在Python中捕获的异常的名称？(How to get name of exception that was caught in Python?)

如何获取在Python中捕获的异常的名称？(How to get name of exception that was caught in Python?)

如何获取在Python中提出的异常的名称？

例如，

try: foo = bar except Exception as exception: name_of_exception = ??? assert name_of_exception == 'NameError' print "Failed with exception [%s]" % name_of_exception

例如，我捕获多个（或全部）异常，并且想要在错误消息中打印异常的名称。

How can I get the name of an exception that was raised in Python?

e.g.,

try: foo = bar except Exception as exception: name_of_exception = ??? assert name_of_exception == 'NameError' print "Failed with exception [%s]" % name_of_exception

For example, I am catching multiple (or all) exceptions, and want to print the name of the exception in an error message.

最满意答案

以下是获取异常名称的两种不同方法：

type(exception).__name__ exception.__class__.__name__

例如，

try: foo = bar except Exception as exception: assert type(exception).__name__ == 'NameError' assert exception.__class__.__name__ == 'NameError'

Here are two different ways to get the name of the exception:

type(exception).__name__ exception.__class__.__name__

e.g.,

try: foo = bar except Exception as exception: assert type(exception).__name__ == 'NameError' assert exception.__class__.__name__ == 'NameError'