Matlab日期向量(Matlab Date Vector)

Matlab日期向量(Matlab Date Vector)

我有一个数组A，其中包含hhmmss格式的时间信息。 最后，我想通过指示经过的时间（以秒为单位，从第一次开始）来规范化此数组。

A = [150213 150013 145813 145613 145413 145313 145213 145113 145013 144943 144913 144843 144833 144823 144813 144803 144753 144743 144741 144739 144737 144735 144733 144731 144729 144727 144725 144723 144721 144719]

所以，最后数组应该是：

A_updated = [894 774 654 534 414 354 294 234 174 144 114 84 74 64 54 44 34 24 22 20 18 16 14 12 10 8 6 4 2 0]

什么是最快的'Matlab方式'继续这个？ 非常感谢你的想法。

I have an array A with time information in the format hhmmss. Ultimately, I would like to normalize this array by indicating the elapsed time (in seconds, starting from the first time).

A = [ 150213 150013 145813 145613 145413 145313 145213 145113 145013 144943 144913 144843 144833 144823 144813 144803 144753 144743 144741 144739 144737 144735 144733 144731 144729 144727 144725 144723 144721 144719]

So, in the end the array should be :

A_updated = [894 774 654 534 414 354 294 234 174 144 114 84 74 64 54 44 34 24 22 20 18 16 14 12 10 8 6 4 2 0 ]

What would be the quickest 'Matlab way' to proceed with this? Many thanks in advance for your ideas.

最满意答案

我暂时没有使用过Matlab，所以原谅语法错误，我现在还没有它，但是这就是我想要的。 基本上，将所有内容转换为秒，然后减去最后一个元素。

At = uint32(A); A_updated = mod(At,100); At = floor(At ./ 100); A_updated = A_updated + mod(At,100) * 60; At = floor(At ./ 100); A_updated = A_updated + At * 3600; A_updated = A_updated - A_updated(end);

I haven't used Matlab in a while, so forgive the syntax mistakes, and I don't have it available right now, but here's what I would try. Basically, convert everything to seconds then subtract the last element.

At = uint32(A); A_updated = mod(At,100); At = floor(At ./ 100); A_updated = A_updated + mod(At,100) * 60; At = floor(At ./ 100); A_updated = A_updated + At * 3600; A_updated = A_updated - A_updated(end);